Steiner-LehumsTheorem revisited
by luimichael, Mar 15, 2017, 9:43 AM
In
, if the angle bisectors of
and
are the same, then
=
.
This is the famous Steiner_Lehmus Theorem. Recently when I calculated the length of angle bisector of a triangle I found a direct proof of the theorem.
Length of angle bisector
Proof of theorem by calculation





This is the famous Steiner_Lehmus Theorem. Recently when I calculated the length of angle bisector of a triangle I found a direct proof of the theorem.
Length of angle bisector
Let BX be the angle bisector of
where X lies on AC. Let
.
By angle bisector theorem,
. Therefore we may let
and
.
But AC =b,
. Then
and 
Apply Steward's Theorem:






By angle bisector theorem,



But AC =b,



Apply Steward's Theorem:




Proof of theorem by calculation
Let CY be the angle bisector of
and
.
Then
By assumption

After simplification and factorization:
![$(a+b+c)(b-c)[a^2+a^2(b+c)+3abc+bc(b+c)]=0$](//latex.artofproblemsolving.com/9/9/c/99c01e655da40a40438da1364f7e66d4bc203918.png)
This implies
because the other two factors are positive.
Hence
.


Then

By assumption


After simplification and factorization:
![$(a+b+c)(b-c)[a^2+a^2(b+c)+3abc+bc(b+c)]=0$](http://latex.artofproblemsolving.com/9/9/c/99c01e655da40a40438da1364f7e66d4bc203918.png)
This implies

Hence
