Some identities

by luimichael, Apr 1, 2017, 3:24 PM

$$\sum_{k=1}^n k C_k^n=n 2^{n-1}$$$$\sum_{k=1}^n k^2 C_k^n=n(n+1) 2^{n-2}$$$$\sum_{k=1}^n k^3 C_k^n=n^2(n+3) 2^{n-3}$$proof

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