Flat Unramified extension of DVR
by iarnab_kundu, Oct 23, 2017, 9:46 AM
A flat extension of rings is one where
is flat as an
module. An unramified extension of Noetherian local rings
is one where the maximal ideal
of
generates the maximal ideal of
, that is
is the maximal ideal of
; and the residue field extension
is a finite separable extension.
Lemma: If
is an unramified extension of Noetherian local rings. Suppose
is any ring extension. Then
is an \etale map.
Lemma: Let
,
be Noetherian local rings with maximal ideal
and
respectively. If
is a flat unramified extension of local rings. Then
is an isomorphism of rings, where the map is given by
.
Proof: Consider the exact sequence
. Given that
is flat, tensoring with
produces the sequence
. We have used the fact that
is an isomorphism, where the map is
.
Lemma: Flat module over an integral domain is torsion free.
Lemma: (Krull's intersection theorem) Let
be a Noetherian local ring, with a proper ideal
. Then
.
Lemma: Let
,
be Noetherian local rings with maximal ideals
and
respectively. Suppose
is a dvr, and
is a flat, unramified extension. Then
is a integral domain.
Proof: At the outset, assume that
is not a field. Let
be a coordinate of
. Then by the unramifiedness we have that
generates
. If
then the maximal ideal
implying that
is a field; and therefore we may assume
. We shall first prove that
is not nilpotent. Suppose on the contrary
is nilpotent. Choose the smallest
such that
. But
being flat over an integral domain, is in fact torsion free. However,
. Thus,
, which contradicts the minimality of
.Thus we have proved that
is not nilpotent.
Now we shall prove that
is an integral domain. Suppose there are non-zero zero-divisors,
and
. By Krull's intersection theorem we have that there is a positive integer
such that
. Hence we may factor
where
and is therefore a unit. Similarly there is a positive integer
and a unit
such that
. Then
, which implies that
is nilpotent. Thus we are done.
Corrollary: With
be Noetherian local rings as above. If
is a dvr, and
is a flat unramified extension of rings; then
is also a dvr.
Proof: We shall follow through the above proof. We have already shown that
is an integral domain, and that
generates the maximal ideal
. From the proof it is also clear that any element
can be written as
where
is a positive integer and
is a unit. We may now show that
is a UFD, and therefore
being principal is of height
. Thus the result follows.









Lemma: If



Lemma: Let







Proof: Consider the exact sequence






Lemma: Flat module over an integral domain is torsion free.
Lemma: (Krull's intersection theorem) Let



Lemma: Let







Proof: At the outset, assume that


















Now we shall prove that












Corrollary: With




Proof: We shall follow through the above proof. We have already shown that










This post has been edited 5 times. Last edited by iarnab_kundu, Oct 24, 2017, 10:31 AM