quite tough

by hemangsarkar, Sep 10, 2012, 6:32 AM

Q) find the number of real solutions of -
$|3 - 3^x| + |1 - 3^x| = 1 - 3^x - \frac{3^{-x}}{4}$

solution : $|3 - 3^x| + |1 - 3^x| \geq |(3-3^x) + (1 - 3^x)| = 2$



$1 - 3^x - \frac{3^{-x}}{4} = 1- \left(3^x +\frac{3^{-x}}{4} \right) = 1 - \left(\left(3^{x/2} + \frac{3^{-x/2}}{2} \right)^2 - 2*3^{x/2} *\frac{3^{-x/2}}{2} \right) = 2 - \left(3^{x/2} + \frac{3^{-x/2}}{2} \right)^2 < 2$


so no real solutions.

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How did you arrive at (3-3^x+1-3^x)=2?

by Sampro, Sep 12, 2012, 5:51 AM

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    by Pheonix, Sep 6, 2012, 5:09 PM

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