nice problem.
by hemangsarkar, Oct 2, 2012, 7:43 PM
let
be a differentiable function such that

for all real
and
. also 
find the value of of the following -
1)
2) the range of
my solution
define a new function
for all
.
so we have
this implies that
where
is some constant.
hence
implies that
.
. putting
in
we get
.
so
is a point of local and absolute minimum.
the minimum value is
range is![$\left[\frac{-2}{e},\infty \right]$](//latex.artofproblemsolving.com/2/8/0/2803a557cdb52e4781dd8c4c3e7241807e9342fb.png)
the solution in the book


for all real



find the value of of the following -
1)

2) the range of

my solution

define a new function


so we have

this implies that


hence







so

the minimum value is

range is
![$\left[\frac{-2}{e},\infty \right]$](http://latex.artofproblemsolving.com/2/8/0/2803a557cdb52e4781dd8c4c3e7241807e9342fb.png)
the solution in the book
differentiate with respect to
keeping
as constant.
put
. you will get a linear differential equation. use the
integrating factor to find the result.


put

integrating factor to find the result.