The Curse of the 8th Dimension
by greenturtle3141, Nov 19, 2023, 9:40 PM
Prerequisites: A Rough Understanding of Calculus
Reading Difficulty: 4/5
Today's post is a real treat! But before we dig in, I want to make sure we're all on the same page on an important term that we're going to use: "Smooth".
For the layman reader, an object is "smooth" if it is perfectly round. Things like spheres and ovals are smooth. Squares and triangles are not smooth because the corners are sharp. The graphs of nice functions such as
and
are also smooth.
For the somewhat more knowledgeable reader, we say a function is smooth if you can differentiate it as many times as you want. That's why
is smooth, but the function
is not because you can't take the derivative of
at
. For multivariate functions like
, you'd be invoking the partial derivatives to assess smoothness.
I won't define precisely how you assess smoothness of things that can't really be modeled as the graph of a function, such as 2D surfaces in 3D space or wacky 1D curves in 2D space, but a bunch of the intuition for what it means to be "smooth" carries over.
Ok cool. Now we can have fun.
Minimal Surfaces
Let
and
be two distinct points in a plane. What is the shortest curve whose endpoints are
and
?
The answer, of course, is the line segment between
and
. Thus, this segment is an example of a minimal surface. As you should expect from the terminology, we usually speak of "minimal surfaces" when in higher dimensions. The definition of a minimal surface in 3D space follows essentially the same idea: If you fix a 1D "boundary" or "edge", such as this closed loop,
then what is the surface with smallest surface area that has that boundary? The answer to this question is called a minimal surface.

The Scheck Surface
sorry idk why this is so small
A very illustrative example of a minimal surface in 3D is a catenoid:
The catenoid is the 2D surface of smallest surface area whose boundary/edge is given by two fixed circles. This is why a bubble will appear to curve inward when you put it between two loops:
Are minimal surfaces in 3D space always smooth? The answer is yes! That's not surprising whatsoever. After all, have you ever seen a bubble with sharp corners? That would be really strange!
Even Higher Dimensions
To recap what a minimal surface in 3D space is:
We can also try thinking about minimal surface in higher dimensions, like
! Though, it's pretty hard to visualize. The definition of a minimal surface in super high dimensions is essentially the same: For any positive integer
...
Again, don't worry if you cannot picture what that would look like. I can't really imagine what this looks like either. Anyways, now we can ask the same question!
In 4D space, it turns out that every (3D) minimal surface is smooth.
In 5D space, it turns out that every (4D) minimal surface is smooth.
In 6D space, it turns out that every (5D) minimal surface is smooth.
In 7D space, it turns out that every (6D) minimal surface is smooth.
If there is any justice in the world, surely this pattern will continue! Obviously, any minimal surface should be smooth... I mean, come on, have you ever seen an
-dimensional bubble that has corners? That would be insa-
The Curse of Dimension 8
WHAT? THERE'S A 7 DIMENSIONAL MINIMAL SURFACE EMBEDDED IN 8 DIMENSIONAL SPACE THAT HAS A CORNER???
In 1968, mathematician Simons invented the Simons Cone, which is defined as the set of all points
which satisfy:
I would love to draw a picture of this, but drawing 7-dimensional objects is pretty hard. Here is an incredibly inaccurate diagram:
To make this more accurate, you need to mentally replace the
plane with a 4-dimensional space, and then you need to replace the
axis with another 4-dimensional space. As the inaccurate picture suggests, this is not a smooth surface because there is a sharp corner at the origin!
Simons figured out that if you change this surface slightly, then the surface area changes very little, so he conjectured that the Simons Cone is a minimal surface. In 1969, Bombieri, De Giorgi, and Giusti proved his claim, hence demonstrating for the first time that there exists a non-smooth minimal surface. In 2009, G. De Philippis (an NYU professor!) and E. Paolini came up with a simpler proof, which you can find at https://ems.press/content/serial-article-files/6405.
For the advanced reader: It turns out that any
-dimensional minimal surface in
is smooth when
, and for
, it can be shown that the singularities of a minimal surface have Hausdorff dimension at most
.
But where does
come from?
The exact reason is kinda above my paygrade, but I did some digging. A proof that minimal surfaces are always smooth in
and lower dimensions is buried somewhere in Minimal Varieties in Riemannian Manifolds (1968)... and it's quite a big read. From what I understand, here is why counterexamples like the Simons Cone seem to fail in dimensions
and below:
Now, if my understanding is right, the result above about cones can be used to argue that minimal surfaces in
are always smooth. I think the argument goes something like this:
That's all for today. I hope you are now slightly more disturbed about the mathematical world!
Reading Difficulty: 4/5
Today's post is a real treat! But before we dig in, I want to make sure we're all on the same page on an important term that we're going to use: "Smooth".
For the layman reader, an object is "smooth" if it is perfectly round. Things like spheres and ovals are smooth. Squares and triangles are not smooth because the corners are sharp. The graphs of nice functions such as


For the somewhat more knowledgeable reader, we say a function is smooth if you can differentiate it as many times as you want. That's why





I won't define precisely how you assess smoothness of things that can't really be modeled as the graph of a function, such as 2D surfaces in 3D space or wacky 1D curves in 2D space, but a bunch of the intuition for what it means to be "smooth" carries over.
Ok cool. Now we can have fun.
Minimal Surfaces
Let




The answer, of course, is the line segment between



then what is the surface with smallest surface area that has that boundary? The answer to this question is called a minimal surface.

The Scheck Surface
sorry idk why this is so small
A very illustrative example of a minimal surface in 3D is a catenoid:

The catenoid is the 2D surface of smallest surface area whose boundary/edge is given by two fixed circles. This is why a bubble will appear to curve inward when you put it between two loops:

Are minimal surfaces in 3D space always smooth? The answer is yes! That's not surprising whatsoever. After all, have you ever seen a bubble with sharp corners? That would be really strange!
Even Higher Dimensions
To recap what a minimal surface in 3D space is:
A minimal surface in
is a 2D surface of minimum (two dimensional) area given a prescribed (one dimensional) boundary.

We can also try thinking about minimal surface in higher dimensions, like


A minimal surface in
is an
-dimensional surface of minimum (
-dimensional) area given a prescribed (
-dimensional) boundary.




Again, don't worry if you cannot picture what that would look like. I can't really imagine what this looks like either. Anyways, now we can ask the same question!
Are minimal surfaces in
-dimensional space always smooth?

In 4D space, it turns out that every (3D) minimal surface is smooth.
In 5D space, it turns out that every (4D) minimal surface is smooth.
In 6D space, it turns out that every (5D) minimal surface is smooth.
In 7D space, it turns out that every (6D) minimal surface is smooth.
If there is any justice in the world, surely this pattern will continue! Obviously, any minimal surface should be smooth... I mean, come on, have you ever seen an

The Curse of Dimension 8
WHAT? THERE'S A 7 DIMENSIONAL MINIMAL SURFACE EMBEDDED IN 8 DIMENSIONAL SPACE THAT HAS A CORNER???
In 1968, mathematician Simons invented the Simons Cone, which is defined as the set of all points





Simons figured out that if you change this surface slightly, then the surface area changes very little, so he conjectured that the Simons Cone is a minimal surface. In 1969, Bombieri, De Giorgi, and Giusti proved his claim, hence demonstrating for the first time that there exists a non-smooth minimal surface. In 2009, G. De Philippis (an NYU professor!) and E. Paolini came up with a simpler proof, which you can find at https://ems.press/content/serial-article-files/6405.
For the advanced reader: It turns out that any





But where does

The exact reason is kinda above my paygrade, but I did some digging. A proof that minimal surfaces are always smooth in


- We lose a dimension by considering only the base of the cone, so now we're considering dimension
and below.
- We go down to
dimensions because in
dimensional space, (codimension 1) surfaces are
dimensional.
- So the dimension of a certain thing is
with
. The key quantity, for some reason, is the expression
and this happens to be negative exactly when
. When this quantity is negative, it can be shown that cones can't be minimal surfaces. But when
, this quantity is positive, so the argument breaks.
Now, if my understanding is right, the result above about cones can be used to argue that minimal surfaces in

- It suffices to consider "locally minimizing", i.e. just need to look at the part of a surface near a given point.
- From a theorem by De Giorgi, if the surface is minimizing, then it should look like a plane if you zoom in far enough into the point.
- From this "blow-up argument", you can thus instead think about "globally minimizing" surfaces, since you can blow up a surface to fill the entirety of space or something. Federer was probably involved at some point here.
- Finally, when you're in
, you can prove that the type of minimal surface in question needs to be a plane, and to get the desired contradiction here, it turns out that using the idea of cones is very useful.
That's all for today. I hope you are now slightly more disturbed about the mathematical world!
This post has been edited 7 times. Last edited by greenturtle3141, Nov 19, 2023, 9:50 PM