IMO Solution mistake
by CHESSR1DER, May 16, 2025, 7:35 AM
I found a mistake in 4th solution at IMO 1982/1. It gives answer
and
. But right answer is only
. Should it be reported somewhere in Aops?



IMO
L
power of a point
by BekzodMarupov, May 16, 2025, 5:41 AM
Epsilon 1.3. Let ABC be a triangle and let D, E, F be the feet of the altitudes, with D on BC, E on CA, and F on AB. Let the parallel through D to EF meet AB at X and AC at Y. Let T be the intersection of EF with BC and let M be the midpoint of side BC. Prove that the points T, M, X, Y are concyclic.
4-vars inequality
by xytunghoanh, May 15, 2025, 2:10 PM
For
and
,
. Prove that
.




This post has been edited 1 time. Last edited by xytunghoanh, Yesterday at 2:16 PM
Reason: add condition
Reason: add condition
inequality
by mathematical-forest, May 15, 2025, 12:40 PM
Ah, easy one
by irregular22104, May 14, 2025, 4:01 PM
In the number series
every next number (from the fifth number) is the unit number of the sum of the four numbers preceding it. Is there any cases that we get the numbers
and
in this series?



Hard geometry
by Lukariman, May 14, 2025, 4:28 AM
Given circle (O) and chord AB with different diameters. The tangents of circle (O) at A and B intersect at point P. On the small arc AB, take point C so that triangle CAB is not isosceles. The lines CA and BP intersect at D, BC and AP intersect at E. Prove that the centers of the circles circumscribing triangles ACE, BCD and OPC are collinear.
This post has been edited 2 times. Last edited by Lukariman, May 14, 2025, 4:49 AM
Functional Equation!
by EthanWYX2009, Mar 29, 2025, 10:48 AM
Find all functions
such that
is unbounded and
is a perfect square for all integer 


![\[2f(m)f(n)-f(n-m)-1\]](http://latex.artofproblemsolving.com/0/f/7/0f77b5addbf8f5e603eb1b6923cdac795cd132e9.png)

IMO Shortlist 2014 G3
by hajimbrak, Jul 11, 2015, 8:49 AM
Let
and
be the circumcircle and the circumcentre of an acute-angled triangle
with
. The angle bisector of
intersects
at
. Let
be the circle with diameter
. The angle bisectors of
and
intersect
at points
and
respectively. The point
is chosen on the line
so that
. Prove that
.
(Here we always assume that an angle bisector is a ray.)
Proposed by Sergey Berlov, Russia


















(Here we always assume that an angle bisector is a ray.)
Proposed by Sergey Berlov, Russia
This post has been edited 2 times. Last edited by hajimbrak, Jul 23, 2015, 10:35 AM
Reason: Added proposer
Reason: Added proposer
Eight-point cicle
by sandu2508, May 4, 2010, 12:21 PM
Let
be an acute triangle with orthocentre
, and let
be the midpoint of
. The point
on
is such that
is an altitude of the triangle
. Let
be the reflection of
in
. The orthogonal projections of
onto the lines
,
and
are
,
and
, respectively. Let
be the point such that the circumcentre of triangle
is the midpoint of the segment
.
Prove that
lies on the segment
.





















Prove that


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