[MOM] What I do home alone on a Sunday night...

by shiningsunnyday, Sep 11, 2016, 4:39 PM

Mongolian TST / Lemmas in Oly Geo wrote:
Let $O$ be the circumcenter of the acute-angled triangle $ABC,$ and let $M$ be a point on the circumcircle of triangle $ABC.$ Let $X, Y, Z$ be the projections of $M$ onto $OA, OB, OC,$ respectively. Prove that the incenter of triangle $XYZ$ lies on the Simson line of $M$ with respect to triangle $ABC.$
Solution
Tidbit
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This post has been edited 1 time. Last edited by shiningsunnyday, Sep 11, 2016, 4:40 PM

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You are good at drawing and your handwriting is neat... things I have never managed to nail down :( :( :noo: :noo:

by zephyrcrush78, Sep 11, 2016, 5:39 PM

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ayy I think I see it

homothety at M, then show that I under homothety still lies on the line.

Yea that's a nice first step. But we don't know much about the image of I, so what you gonna do next birdie (though I kind of drew it in the diagram oops).
This post has been edited 1 time. Last edited by shiningsunnyday, Sep 12, 2016, 5:55 PM

by agbdmrbirdyface, Sep 11, 2016, 6:28 PM

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ssd

please sleep

i’m concerned

by cjquines0, Sep 12, 2016, 1:38 AM

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hm i think i have a sol without using fact that simson line bisects $MH$

note

Hm that's an interesting observation; I'll see where I can get with it sometime in the near future; also my words in the margin lead to a dead end lol; I ended up using an entirely different approach
This post has been edited 2 times. Last edited by shiningsunnyday, Sep 12, 2016, 5:58 PM

by tastymath75025, Sep 12, 2016, 3:38 AM

To share with readers my favorite problem I came across today :) (Shout for contrib.)

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  • Let $ ABC$ be an equilateral triangle of side length $ 1$. Let $ D$ be the point such that $ C$ is the midpoint of $ BD$, and let $ I$ be the incenter of triangle $ ACD$. Let $ E$ be the point on line $ AB$ such that $ DE$ and $ BI$ are perpendicular. $ \

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