Birthday power

by shiningsunnyday, Apr 15, 2017, 2:56 AM

2009 USAMO 1 wrote:
Given circles $ \omega_1$ and $ \omega_2$ intersecting at points $ X$ and $ Y$, let $ \ell_1$ be a line through the center of $ \omega_1$ intersecting $ \omega_2$ at points $ P$ and $ Q$ and let $ \ell_2$ be a line through the center of $ \omega_2$ intersecting $ \omega_1$ at points $ R$ and $ S$. Prove that if $ P, Q, R$ and $ S$ lie on a circle then the center of this circle lies on line $ XY$.

Solution

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4 Comments

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That's an example in EGMO btw

by MathAwesome123, Apr 15, 2017, 3:01 AM

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Wait actually that solution is incorrect.

RIP. Good point - will fix later
This post has been edited 1 time. Last edited by shiningsunnyday, Apr 15, 2017, 3:17 AM

by MathAwesome123, Apr 15, 2017, 3:03 AM

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Even so, that additional complication was the hard part of the problem anyway.

by MathAwesome123, Apr 15, 2017, 3:08 AM

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The PoP solution avoid configuration issues.

by First, Apr 15, 2017, 3:14 AM

To share with readers my favorite problem I came across today :) (Shout for contrib.)

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  • Let $ ABC$ be an equilateral triangle of side length $ 1$. Let $ D$ be the point such that $ C$ is the midpoint of $ BD$, and let $ I$ be the incenter of triangle $ ACD$. Let $ E$ be the point on line $ AB$ such that $ DE$ and $ BI$ are perpendicular. $ \

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