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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Yesterday at 3:18 PM
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
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April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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0 replies
jlacosta
Yesterday at 3:18 PM
0 replies
k i Adding contests to the Contest Collections
dcouchman   1
N Apr 5, 2023 by v_Enhance
Want to help AoPS remain a valuable Olympiad resource? Help us add contests to AoPS's Contest Collections.

Find instructions and a list of contests to add here: https://artofproblemsolving.com/community/c40244h1064480_contests_to_add
1 reply
dcouchman
Sep 9, 2019
v_Enhance
Apr 5, 2023
k i Zero tolerance
ZetaX   49
N May 4, 2019 by NoDealsHere
Source: Use your common sense! (enough is enough)
Some users don't want to learn, some other simply ignore advises.
But please follow the following guideline:


To make it short: ALWAYS USE YOUR COMMON SENSE IF POSTING!
If you don't have common sense, don't post.


More specifically:

For new threads:


a) Good, meaningful title:
The title has to say what the problem is about in best way possible.
If that title occured already, it's definitely bad. And contest names aren't good either.
That's in fact a requirement for being able to search old problems.

Examples:
Bad titles:
- "Hard"/"Medium"/"Easy" (if you find it so cool how hard/easy it is, tell it in the post and use a title that tells us the problem)
- "Number Theory" (hey guy, guess why this forum's named that way¿ and is it the only such problem on earth¿)
- "Fibonacci" (there are millions of Fibonacci problems out there, all posted and named the same...)
- "Chinese TST 2003" (does this say anything about the problem¿)
Good titles:
- "On divisors of a³+2b³+4c³-6abc"
- "Number of solutions to x²+y²=6z²"
- "Fibonacci numbers are never squares"


b) Use search function:
Before posting a "new" problem spend at least two, better five, minutes to look if this problem was posted before. If it was, don't repost it. If you have anything important to say on topic, post it in one of the older threads.
If the thread is locked cause of this, use search function.

Update (by Amir Hossein). The best way to search for two keywords in AoPS is to input
[code]+"first keyword" +"second keyword"[/code]
so that any post containing both strings "first word" and "second form".


c) Good problem statement:
Some recent really bad post was:
[quote]$lim_{n\to 1}^{+\infty}\frac{1}{n}-lnn$[/quote]
It contains no question and no answer.
If you do this, too, you are on the best way to get your thread deleted. Write everything clearly, define where your variables come from (and define the "natural" numbers if used). Additionally read your post at least twice before submitting. After you sent it, read it again and use the Edit-Button if necessary to correct errors.


For answers to already existing threads:


d) Of any interest and with content:
Don't post things that are more trivial than completely obvious. For example, if the question is to solve $x^{3}+y^{3}=z^{3}$, do not answer with "$x=y=z=0$ is a solution" only. Either you post any kind of proof or at least something unexpected (like "$x=1337, y=481, z=42$ is the smallest solution). Someone that does not see that $x=y=z=0$ is a solution of the above without your post is completely wrong here, this is an IMO-level forum.
Similar, posting "I have solved this problem" but not posting anything else is not welcome; it even looks that you just want to show off what a genius you are.

e) Well written and checked answers:
Like c) for new threads, check your solutions at least twice for mistakes. And after sending, read it again and use the Edit-Button if necessary to correct errors.



To repeat it: ALWAYS USE YOUR COMMON SENSE IF POSTING!


Everything definitely out of range of common sense will be locked or deleted (exept for new users having less than about 42 posts, they are newbies and need/get some time to learn).

The above rules will be applied from next monday (5. march of 2007).
Feel free to discuss on this here.
49 replies
ZetaX
Feb 27, 2007
NoDealsHere
May 4, 2019
Problem inequality
inversionA007   10
N a few seconds ago by Primeniyazidayi
Let $x>0, y>0, z>0$ and satisfy $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=3$. Prove that $
x^2+y^2+z^2-2 x y z \geq 1$.
10 replies
inversionA007
Jan 14, 2024
Primeniyazidayi
a few seconds ago
Is it boring?
FAA2533   7
N a minute ago by TheMatrix2024
Source: BdMO 2025 Secondary P2
Find all real solutions to the equation $(x^2-9x+19)^{x^2-3x+2} = 1$.
7 replies
FAA2533
Feb 8, 2025
TheMatrix2024
a minute ago
Very interesting inequalities
sqing   2
N 4 minutes ago by sqing
Source: Own
Let $ a,b,c> 0 $ and $ab+bc+ca+abc =4. $ Prove that
$$  \frac{15}{ a+b+c}+\frac{4}{abc}   \geq  9$$
2 replies
sqing
Mar 31, 2025
sqing
4 minutes ago
Inspired by Ecrin_eren
sqing   0
8 minutes ago
Source: Own
Let $  x ,y\geq 0 $ and $ x^2(y^2 + 9) + x^4y + 3y^2 \geq 27.$ Prove that
$$x^2 -x+ \frac{1}{2}y\geq 1$$$$x^2 -x+ \frac{1}{3}y\geq \frac{5}{8}$$$$x^2  -x+  y\geq 3-\sqrt 3$$
0 replies
1 viewing
sqing
8 minutes ago
0 replies
Inequality
SunnyEvan   3
N 24 minutes ago by DKI
Let $a$, $b$, $c$ be non-negative real numbers, no two of which are zero. Prove that :
$$ \sum \frac{3ab-2bc+3ca}{3b^2+bc+3c^2} \geq \frac{12}{7}$$
3 replies
SunnyEvan
Tuesday at 9:54 AM
DKI
24 minutes ago
Mmo 9-10 graders P5
Bet667   3
N 41 minutes ago by Quantum-Phantom
Let $a,b,c,d$ be real numbers less than 2.Then prove that $\frac{a^3}{b^2+4}+\frac{b^3}{c^2+4}+\frac{c^3}{d^2+4}+\frac{d^3}{a^2+4}\le4$
3 replies
Bet667
2 hours ago
Quantum-Phantom
41 minutes ago
A number theory problem from the British Math Olympiad
Rainbow1971   13
N an hour ago by ektorasmiliotis
Source: British Math Olympiad, 2006/2007, round 1, problem 6
I am a little surprised to find that I am (so far) unable to solve this little problem:

[quote]Let $n$ be an integer. Show that, if $2 + 2 \sqrt{1+12n^2}$ is an integer, then it is a perfect square.[/quote]

I set $k := \sqrt{1+12n^2}$. If $2 + 2 \sqrt{1+12n^2}$ is an integer, then $k (=\sqrt{1+12n^2})$ is at least rational, so that $1 + 12n^2$ must be a perfect square then. Using Conway's topograph method, I have found out that the smallest non-negative pairs $(n, k)$ for which this happens are $(0,1), (2,7), (28,97)$ and $(390, 1351)$, and that, for every such pair $(n,k)$, the "next" such pair can be calculated as
$$
\begin{bmatrix}
7 & 2 \\
24 & 7 
\end{bmatrix} \begin{bmatrix}
n \\
k 
\end{bmatrix}
.$$The eigenvalues of that matrix are irrational, however, so that any calculation which uses powers of that matrix is a little cumbersome. There must be an easier way, but I cannot find it. Can you?

Thank you.




13 replies
Rainbow1971
Mar 28, 2025
ektorasmiliotis
an hour ago
inequalities
Cobedangiu   9
N an hour ago by DKI
problem
9 replies
Cobedangiu
Mar 31, 2025
DKI
an hour ago
All Black Cells
David-Vieta   8
N an hour ago by sato2718
Source: 2023 China TST Problem 24
Let $n$ be a positive integer. Initially, a $2n \times 2n$ grid has $k$ black cells and the rest white cells. The following two operations are allowed :
(1) If a $2\times 2$ square has exactly three black cells, the fourth is changed to a black cell;
(2) If there are exactly two black cells in a $2 \times 2$ square, the black cells are changed to white and white to black.
Find the smallest positive integer $k$ such that for any configuration of the $2n \times 2n$ grid with $k$ black cells, all cells can be black after a finite number of operations.
8 replies
David-Vieta
Apr 1, 2023
sato2718
an hour ago
Similar triangles and parallelism
KAME06   2
N 2 hours ago by jordiejoh
Source: OMEC Ecuador National Olympiad Final Round 2022 N3 P5 day 2
Let $ABC$ be a 90-degree triangle with hypotenuse $BC$. Let $D$ and $E$ distinct points on segment $BC$ and $P, Q$ be the foot of the perpendicular from $D$ to $AB$ and $E$ to $AC$, respectively. $DP$ and $EQ$ intersect at $R$.
Lines $CR$ and $AB$ intersect at $M$ and lines $BR$ and $AC$ intersect at $N$.
Prove that $MN \parallel BC$ if and only if $BD=CE$.
2 replies
KAME06
Nov 4, 2024
jordiejoh
2 hours ago
Modular Matching Pairs
steven_zhang123   2
N 2 hours ago by CHN_Lucas
Source: China TST 2025 P20
Let \( n \) be an odd integer, \( m = \frac{n+1}{2} \). Consider \( 2m \) integers \( a_1, a_2, \ldots, a_m, b_1, b_2, \ldots, b_m \) such that for any \( 1 \leq i < j \leq m \), \( a_i \not\equiv a_j \pmod{n} \) and \( b_i \not\equiv b_j \pmod{n} \). Prove that the number of \( k \in \{0, 1, \ldots, n-1\} \) for which satisfy \( a_i + b_j \equiv k \pmod{n} \) for some \( i \neq j \), $i, j \in \left \{ 1,2,\cdots,m \right \} $ is greater than \( n - \sqrt{n} - \frac{1}{2} \).
2 replies
steven_zhang123
Mar 29, 2025
CHN_Lucas
2 hours ago
Turkish MO 1994 P5
xeroxia   9
N 2 hours ago by Primeniyazidayi
Source: Turkish Mathematical Olympiad 2nd Round 1994
Find the set of all ordered pairs $(s,t)$ of positive integers such that \[t^{2}+1=s(s+1).\]
9 replies
1 viewing
xeroxia
Sep 27, 2006
Primeniyazidayi
2 hours ago
Another FE
Ankoganit   43
N 2 hours ago by jasperE3
Source: India IMO Training Camp 2016, Practice test 2, Problem 2
Find all functions $f:\mathbb R\to\mathbb R$ such that $$f\left( x^2+xf(y)\right)=xf(x+y)$$for all reals $x,y$.
43 replies
Ankoganit
Jul 22, 2016
jasperE3
2 hours ago
Sequence of numbers in form of a^2+b^2
TheOverlord   12
N 3 hours ago by ihategeo_1969
Source: Iran TST 2015, exam 1, day 1 problem 3
Let $ b_1<b_2<b_3<\dots $ be the sequence of all natural numbers which are sum of squares of two natural numbers.
Prove that there exists infinite natural numbers like $m$ which $b_{m+1}-b_m=2015$ .
12 replies
TheOverlord
May 11, 2015
ihategeo_1969
3 hours ago
draw-triple in a tournament
mr.danh   1
N Feb 7, 2010 by Athinaios
Source: Polish Mathematical Olympiad 2004 Final Round Problem 3
On a tournament with $ n \ge 3$ participants, every two participants played exactly one match and there were no draws. A three-element set of participants is called a draw-triple if they can be enumerated so that the first defeated the second, the second defeated the third, and the third defeated the first. Determine the largest possible number of draw-triples on such a tournament.
1 reply
mr.danh
Feb 7, 2010
Athinaios
Feb 7, 2010
draw-triple in a tournament
G H J
Source: Polish Mathematical Olympiad 2004 Final Round Problem 3
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mr.danh
635 posts
#1 • 2 Y
Y by Adventure10, Mango247
On a tournament with $ n \ge 3$ participants, every two participants played exactly one match and there were no draws. A three-element set of participants is called a draw-triple if they can be enumerated so that the first defeated the second, the second defeated the third, and the third defeated the first. Determine the largest possible number of draw-triples on such a tournament.
Z K Y
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Athinaios
280 posts
#2 • 1 Y
Y by Adventure10
nice problem.
First we see that $ \{ a,b,c \}$ is not a draw-triple if and only if there is a participant that beats the others two and that also if and only if one participant loses from the other two.
So if we send a participant ,lets say $ x_i$ , to the pair $ (y_i,w_i)$ such that $ x_i$ beats $ y_i$ and loses from $ w_i$ number of participants.

Then $ w_i + y_i = n - 1$

and the draw triples are equal to, $ \binom{n}{3} - \sum_{k = 1}^{n}(\frac {\binom{w_i}{2} + \binom{y_i}{2}}{2})$

now use the inequality $ 2(w_i^2 + y_i^2)\geq (n - 1)^2$ to see that the an upper bound is $ \binom{n} {3} - \frac {n^3 - 4n^2 + 3n}{8}$ (1)

Now the equality.
if $ n$ is odd then take $ y_i = w_i = \frac {n - 1}{2}$ to attain (1)

else with n even see with the same process that
( to be more specific because of the convexicity of binomial coef)
the maximum is attained for example when $ w_i = \frac {n}{2},y_i = \frac {n - 2}{2}$ for every $ i$ and if i am correct in my calculations it is, $ \binom{n}{3} - \frac {n^3 - 4n^2 + 4n}{8}$
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