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k a April Highlights and 2025 AoPS Online Class Information
jlacosta   0
Apr 2, 2025
Spring is in full swing and summer is right around the corner, what are your plans? At AoPS Online our schedule has new classes starting now through July, so be sure to keep your skills sharp and be prepared for the Fall school year! Check out the schedule of upcoming classes below.

WOOT early bird pricing is in effect, don’t miss out! If you took MathWOOT Level 2 last year, no worries, it is all new problems this year! Our Worldwide Online Olympiad Training program is for high school level competitors. AoPS designed these courses to help our top students get the deep focus they need to succeed in their specific competition goals. Check out the details at this link for all our WOOT programs in math, computer science, chemistry, and physics.

Looking for summer camps in math and language arts? Be sure to check out the video-based summer camps offered at the Virtual Campus that are 2- to 4-weeks in duration. There are middle and high school competition math camps as well as Math Beasts camps that review key topics coupled with fun explorations covering areas such as graph theory (Math Beasts Camp 6), cryptography (Math Beasts Camp 7-8), and topology (Math Beasts Camp 8-9)!

Be sure to mark your calendars for the following events:
[list][*]April 3rd (Webinar), 4pm PT/7:00pm ET, Learning with AoPS: Perspectives from a Parent, Math Camp Instructor, and University Professor
[*]April 8th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MATHCOUNTS State Discussion
April 9th (Webinar), 4:00pm PT/7:00pm ET, Learn about Video-based Summer Camps at the Virtual Campus
[*]April 10th (Math Jam), 4:30pm PT/7:30pm ET, 2025 MathILy and MathILy-Er Math Jam: Multibackwards Numbers
[*]April 22nd (Webinar), 4:00pm PT/7:00pm ET, Competitive Programming at AoPS (USACO).[/list]
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All classes run 7:30pm-8:45pm ET/4:30pm - 5:45pm PT unless otherwise noted.

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0 replies
jlacosta
Apr 2, 2025
0 replies
2025 Math and AI 4 Girls Competition: Win Up To $1,000!!!
audio-on   26
N 32 minutes ago by BossLu99
Join the 2025 Math and AI 4 Girls Competition for a chance to win up to $1,000!

Hey Everyone, I'm pleased to announce the dates for the 2025 MA4G Competition are set!
Applications will open on March 22nd, 2025, and they will close on April 26th, 2025 (@ 11:59pm PST).

Applicants will have one month to fill out an application with prizes for the top 50 contestants & cash prizes for the top 20 contestants (including $1,000 for the winner!). More details below!

Eligibility:
The competition is free to enter, and open to middle school female students living in the US (5th-8th grade).
Award recipients are selected based on their aptitude, activities and aspirations in STEM.

Event dates:
Applications will open on March 22nd, 2025, and they will close on April 26th, 2025 (by 11:59pm PST)
Winners will be announced on June 28, 2025 during an online award ceremony.

Application requirements:
Complete a 12 question problem set on math and computer science/AI related topics
Write 2 short essays

Prizes:
1st place: $1,000 Cash prize
2nd place: $500 Cash prize
3rd place: $300 Cash prize
4th-10th: $100 Cash prize each
11th-20th: $50 Cash prize each
Top 50 contestants: Over $50 worth of gadgets and stationary


Many thanks to our current and past sponsors and partners: Hudson River Trading, MATHCOUNTS, Hewlett Packard Enterprise, Automation Anywhere, JP Morgan Chase, D.E. Shaw, and AI4ALL.

Math and AI 4 Girls is a nonprofit organization aiming to encourage young girls to develop an interest in math and AI by taking part in STEM competitions and activities at an early age. The organization will be hosting an inaugural Math and AI 4 Girls competition to identify talent and encourage long-term planning of academic and career goals in STEM.

Contact:
mathandAI4girls@yahoo.com

For more information on the competition:
https://www.mathandai4girls.org/math-and-ai-4-girls-competition

More information on how to register will be posted on the website. If you have any questions, please ask here!


26 replies
2 viewing
audio-on
Jan 26, 2025
BossLu99
32 minutes ago
Mathcounts state
happymoose666   19
N 32 minutes ago by BossLu99
Hi everyone,
I just have a question. I live in PA and I sadly didn't make it to nationals this year. Is PA a competitive state? I'm new into mathcounts and not sure
19 replies
+2 w
happymoose666
Mar 24, 2025
BossLu99
32 minutes ago
2n equations
P_Groudon   80
N 4 hours ago by vincentwant
Let $n \geq 4$ be an integer. Find all positive real solutions to the following system of $2n$ equations:

\begin{align*}
a_{1} &=\frac{1}{a_{2 n}}+\frac{1}{a_{2}}, & a_{2}&=a_{1}+a_{3}, \\
a_{3}&=\frac{1}{a_{2}}+\frac{1}{a_{4}}, & a_{4}&=a_{3}+a_{5}, \\
a_{5}&=\frac{1}{a_{4}}+\frac{1}{a_{6}}, & a_{6}&=a_{5}+a_{7} \\
&\vdots & &\vdots \\
a_{2 n-1}&=\frac{1}{a_{2 n-2}}+\frac{1}{a_{2 n}}, & a_{2 n}&=a_{2 n-1}+a_{1}
\end{align*}
80 replies
P_Groudon
Apr 15, 2021
vincentwant
4 hours ago
basic nt
zhoujef000   38
N 5 hours ago by Apple_maths60
Source: 2025 AIME I #1
Find the sum of all integer bases $b>9$ for which $17_b$ is a divisor of $97_b.$
38 replies
zhoujef000
Feb 7, 2025
Apple_maths60
5 hours ago
No more topics!
Hard Mock AMC 10/12
BOGTRO   10
N Feb 3, 2014 by BOGTRO
Obviously there is little time between now and the AMC A, but hopefully people will find this useful anyway. I wrote this for the AAST math team as a practice exam for today, but evidently it proved extremely difficult as we would have had <10 AIME qualifiers based on this test (compared to our usual very high number).

Because this was written specifically for the math team there are a couple of small differences between this and the AMC:
[list]
[*] Several problems ask for the usual "the answer can be expressed in the form $\frac{m}{n}$, find $m+n$", but this test allows cases such as $n=1$. This is done when, for example, it's not immediately obvious that the answer turns out to be an integer without actually solving the problem, so it makes bssolving a little harder.
[*] Most problems reference the name of a math team member (possibly obfuscated) followed by some animal's name. Missing the reference is not a big deal (though many will recognize the return of Kelvin the Frog anyway ;))
[*] These problems are harder than usual. Part of this was intentional to reflect the fact that they should have been paying attention to lectures, so some of the harder problems utilized lecture topics. However, a bigger part of this is that gauging difficulty of easy/mid-level problems is difficult for me to do, so most of the early/middle problems are much more difficult than usual (#8 on the mock 10 caused some excitement for example).[/list]

If you want to take this "officially", you can send me answers and I'll score them (and probably post them here unless requested otherwise). The only reason I'm not just posting this with solutions and leaving it at that is because I haven't actually typed up solutions (or an answer key for that matter), so I'll post those here when that actually happens. I'm not asking for signups or anything because this is so late, so don't fill up this thread with a list of people.

On a final note, I only had about a week to write this test due to being away, so I found it easier to "rip off" (and make easier in some cases) some problems for later AMC 12 problems. I believe I only did this 3 times (#21 [which was specifically placed for a couple of select people], 22 [which was made easier], 25 [which is classic] on AMC 12), but obviously you may have seen problems of similar natures before. Furthermore the shortened timeframe means that there may very well be errors in the problems/answers/solutions (note that this is already a "fixed" version from the earlier 5-errata one). The problem ordering is also a little haphazard - I had to make quick guesses about which problems would supposedly be harder than others. Finally, the mock tests are pretty similar (I formed the AMC 10 by copying and pasting the AMC 12, deleting some hard questions, and adding some easy ones).

I'm not sure what a good normalization factor is, so hopefully some submissions here might help me to figure that out. As such I'd prefer you don't send me answers to grade if you didn't take the test under normal conditions (unless you tell me you didn't take the test under normal conditions), so that I can attempt to figure out just how hard this mock test is. The AMC 10 is much harder than a normal AMC 10, while the AMC 12 seems to only be somewhat harder (who knew that trig wasn't supposed to be on an AMC 10 anyway?).

Enjoy the tests!

Scores

EDIT: By the way, there may be an ASIA TEAM V2 at some point, though Kelvin the Frog is quickly becoming tired and is threatening to go on strike.
EDIT2: Corrected tests updated in this post. Previous download counts were 121 AMC 12 and 147 AMC 10 if anyone was keeping track for some reason.
10 replies
BOGTRO
Feb 2, 2014
BOGTRO
Feb 3, 2014
Hard Mock AMC 10/12
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BOGTRO
5818 posts
#1 • 24 Y
Y by sicilianfan, forthegreatergood, sat113, El_Ectric, Math_Fan, SMOJ, MSTang, Tan, Einstein314, tim9099xxzz, VietaFan, blasterboy, ahaanomegas, JRY, flamefoxx99, Williamgolly, Adventure10, and 7 other users
Obviously there is little time between now and the AMC A, but hopefully people will find this useful anyway. I wrote this for the AAST math team as a practice exam for today, but evidently it proved extremely difficult as we would have had <10 AIME qualifiers based on this test (compared to our usual very high number).

Because this was written specifically for the math team there are a couple of small differences between this and the AMC:
  • Several problems ask for the usual "the answer can be expressed in the form $\frac{m}{n}$, find $m+n$", but this test allows cases such as $n=1$. This is done when, for example, it's not immediately obvious that the answer turns out to be an integer without actually solving the problem, so it makes bssolving a little harder.
  • Most problems reference the name of a math team member (possibly obfuscated) followed by some animal's name. Missing the reference is not a big deal (though many will recognize the return of Kelvin the Frog anyway ;))
  • These problems are harder than usual. Part of this was intentional to reflect the fact that they should have been paying attention to lectures, so some of the harder problems utilized lecture topics. However, a bigger part of this is that gauging difficulty of easy/mid-level problems is difficult for me to do, so most of the early/middle problems are much more difficult than usual (#8 on the mock 10 caused some excitement for example).

If you want to take this "officially", you can send me answers and I'll score them (and probably post them here unless requested otherwise). The only reason I'm not just posting this with solutions and leaving it at that is because I haven't actually typed up solutions (or an answer key for that matter), so I'll post those here when that actually happens. I'm not asking for signups or anything because this is so late, so don't fill up this thread with a list of people.

On a final note, I only had about a week to write this test due to being away, so I found it easier to "rip off" (and make easier in some cases) some problems for later AMC 12 problems. I believe I only did this 3 times (#21 [which was specifically placed for a couple of select people], 22 [which was made easier], 25 [which is classic] on AMC 12), but obviously you may have seen problems of similar natures before. Furthermore the shortened timeframe means that there may very well be errors in the problems/answers/solutions (note that this is already a "fixed" version from the earlier 5-errata one). The problem ordering is also a little haphazard - I had to make quick guesses about which problems would supposedly be harder than others. Finally, the mock tests are pretty similar (I formed the AMC 10 by copying and pasting the AMC 12, deleting some hard questions, and adding some easy ones).

I'm not sure what a good normalization factor is, so hopefully some submissions here might help me to figure that out. As such I'd prefer you don't send me answers to grade if you didn't take the test under normal conditions (unless you tell me you didn't take the test under normal conditions), so that I can attempt to figure out just how hard this mock test is. The AMC 10 is much harder than a normal AMC 10, while the AMC 12 seems to only be somewhat harder (who knew that trig wasn't supposed to be on an AMC 10 anyway?).

Enjoy the tests!

Scores

EDIT: By the way, there may be an ASIA TEAM V2 at some point, though Kelvin the Frog is quickly becoming tired and is threatening to go on strike.
EDIT2: Corrected tests updated in this post. Previous download counts were 121 AMC 12 and 147 AMC 10 if anyone was keeping track for some reason.
Attachments:
MockAMC10.pdf (117kb)
MockAMC12.pdf (136kb)
This post has been edited 2 times. Last edited by BOGTRO, Feb 3, 2014, 6:38 AM
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Math_Fan
410 posts
#2 • 2 Y
Y by Adventure10, Mango247
BOGTRO, do you have the answer key/solutions?
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djmathman
7936 posts
#3 • 3 Y
Y by Math_Fan, Adventure10, Mango247
BOGTRO wrote:
The only reason I'm not just posting this with solutions and leaving it at that is because I haven't actually typed up solutions (or an answer key for that matter), so I'll post those here when that actually happens.
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Math_Fan
410 posts
#4 • 2 Y
Y by Adventure10, Mango247
Sorry about that.
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SMOJ
2663 posts
#5 • 1 Y
Y by Adventure10
Sorry that I do not have your permission yet, but I will post the questions in the forums as there are only 2 days left. Thank you for the questions.
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SMOJ
2663 posts
#6 • 1 Y
Y by Adventure10
AMC 10 Q25 is an olympiad-style question(not an olympiad level question though)
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wcao9311
388 posts
#7 • 3 Y
Y by Adventure10, Mango247, and 1 other user
difficulty is out of wack, first 15 problems are too tedious.
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wcao9311
388 posts
#8 • 2 Y
Y by Adventure10, Mango247
how do you solve #7 on the 12?
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SMOJ
2663 posts
#9 • 1 Y
Y by Adventure10
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=149&t=574108
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BOGTRO
5818 posts
#10 • 2 Y
Y by SMOJ, Adventure10
There have been reports that there is a flawed question (the one involving ratios of sides, #18 on the AMC 12 and #24 (I believe, can't open the documents on phone??) on the AMC 10). I'm only online for a minute so I don't have time to check, but according to trustworthy people the desired ratio should be $\frac{AP}{A_1P}$ (rather than $\frac{B_1P}{BP}$ or whatever it previously asked for). Will be updated at some point.

Also, a lot of the problems have been posted in forums for some reason. Some of them have solutions, but a lot of them either do not, are not posted, or have no correct solution in the thread. Again, I'll be writing a solutions document sometime soon.
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BOGTRO
5818 posts
#11 • 3 Y
Y by MathematicsOfPi, ahaanomegas, Adventure10
Here's some hastily written solutions. I may go back and polish them at some point, but might as well have something out before the AMCs.

You can still PM me to score them if you're too lazy to read the solutions.
Attachments:
BCAAMC10Sol.pdf (134kb)
BCAAMC12Sol.pdf (129kb)
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