A question and some thoughts

by t0rajir0u, Jan 30, 2009, 7:01 AM

Question: Does there exist a satisfying graph-theoretic interpretation of the condition that two graphs are isospectral?

I've been thinking about this question for some time now. I don't really have the background to discuss it in detail, but briefly, the spectrum of a graph is the set of eigenvalues of its adjacency matrix; the powers of those eigenvalues then describes the powers of the adjacency matrix, hence the distribution of paths of length $ n$ on the graph. Intuitively, I think of the spectrum as describing "flows" on a graph.

Two graphs that are isomorphic are also isospectral, but the converse does not hold. This is not surprising: two graphs are isomorphic if and only if their adjacency matrices are similar up to permutation matrices, while two graphs are isospectral if and only if their adjacency matrices are similar up to any invertible matrix in $ \mathbb{C}^n$. Needless to say, this is a much weaker condition, and it's hard to come up with a convincing description of it in graph-theoretic terms.

I have a vague idea that some intermediate notion of isomorphism is possible first by considering weighted graphs and then by finding some way of formalizing what it means to conjugate an adjacency matrix by something other than a (weighted) permutation matrix. But I don't really know what's going on here.

Anyway, the motivation for this question is the following characterization of a class of nilpotent matrices:

Observation. A matrix $ M$ with non-negative real coefficients is nilpotent if and only if it is the weighted adjacency matrix of a directed acyclic graph.

I like this because it is highly intuitive: there are no paths of length greater than $ n$ on a directed acyclic graph on $ n$ vertices, or else they wouldn't be acyclic. A nicely behaved class of directed acyclic graphs is the set of directed trees with edges pointing away from or towards the root. This observation is the basis of the following

Observation. The nilpotent Jordan normal form theorem is (almost) equivalent to the statement that every (weighted) directed acyclic graph is isospectral to a directed [url=hhttp://en.wikipedia.org/wiki/Path_graph]path graph[/url].

Again, I like this because it is highly intuitive. A path is the simplest example of a directed acyclic graph, and to suggest that they are representative of the set of directed acyclic graphs in a particular way is a statement that I think is manageable by other means; I also think such statements should generalize to representative statements about other classes, and it would be very interesting to see the extent to which such statements translated into pure linear algebra.

Along those lines, I have become very interested lately with the idea that linear algebra is really just combinatorics, but I don't think I have the background to understand what Baez really means when he says that. Nevertheless, it is interesting to think about, and is one of the motivations for the above question.

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Hehe, this looks like one of my posts, except you actually go into some background and progress. (though that I don't is intentional)

Have you already gotten Jacob Steinhardt to look at this? He's the first person I'd ask.

Another thing: There's sort of a link between graph theory and linear algebra (adjacency matrices), linear algebra and group theory (representation theory), and group theory and graph theory (not too familiar with details here, but I know several questions can be phrased equivalently in each). I wonder if there's a way to ask this question using groups.

by MellowMelon, Jan 30, 2009, 11:04 PM

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Jacob Steinhardt was in fact the first person I asked. He's getting back to me :P

Well, the issue here is that the nilpotent JNFT deals with non-invertible matrices, so offhand I can't think of a natural way to bring the theory of the general linear groups into this (which would be the obvious "converse" to representation theory). One idea my advisor had when I asked him a related question along these lines is that it might be possible to find out something about a nilpotent matrix $ M$ by computing

$ \frac {1}{I - tM} = 1 + tM + t^2M^2 + ...$

(where the sum terminates.) This is fairly close in line with my hope that it would be possible to prove the nilpotent JNFT using partial fraction decomposition, and the graph-theoretic connection here is to something called the Ihara zeta function, which I can't find any good references on.
This post has been edited 1 time. Last edited by t0rajir0u, Feb 1, 2009, 12:47 AM

by t0rajir0u, Jan 31, 2009, 3:45 AM

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To t0rajir0u:

Your blog is really impressive so I've always wondered what courses you have taken to acquire all of this knowledge.

by JRav, Jan 31, 2009, 6:30 PM

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I'll restrict to the case of $ d$-regular graphs (graphs where all vertices have degree $ d$). Then $ G$ and $ H$ are isotropic if, for every $ n$, the number of closed paths of length $ n$ in $ G$ is equal to the number of closed paths of length $ n$ in $ H$. This is just the basic observation that, if $ A$ and $ B$ are two square matrices, then they are isospectral if and only if $ Tr(A^n) = Tr(B^n)$ for all $ n$.

by Anonymous, Feb 7, 2009, 3:56 PM

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That's an interesting idea, but it doesn't do much in the directed acyclic case; every such graph has no closed walks. Equivalently, they all have Ihara zeta function $ 1$.

The big problem here is that showing that two graphs have similar adjacency matrices is more subtle than showing that they have the same eigenvalues; the adjacency matrix of every directed nilpotent graph has only $ 0$ eigenvalues, but what we are interested in is the distinction between geometric and algebraic multiplicity (i.e. the nature of the connected components of the isospectral graph path), which is perhaps too subtle to capture by graph-theoretic means.

by t0rajir0u, Feb 9, 2009, 1:00 AM

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