Own made functional equation

by JARP091, May 31, 2025, 4:10 PM

\[
\text{Find all functions } f : \mathbb{R} \to \mathbb{R} \text{ such that:} \\
f(a^4 + a^2b^2 + b^4) = f\left((a^2 - f(ab) + b^2)(a^2 + f(ab) + b^2)\right)
\]
This post has been edited 1 time. Last edited by JARP091, 2 hours ago

Inequality conjecture

by RainbowNeos, May 29, 2025, 1:03 PM

Show (or deny) that there exists an absolute constant $C>0$ that, for all $n$ and $n$ positive real numbers $x_i ,1\leq i \leq n$, there is
\[\sum_{i=1}^n \frac{x_i^2}{\sum_{j=1}^i x_j}\geq C \ln n\left(\prod_{i=1}^n x_i\right)^{\frac{1}{n}}\]

Serbian selection contest for the IMO 2025 - P6

by OgnjenTesic, May 22, 2025, 4:07 PM

For an $n \times n$ table filled with natural numbers, we say it is a divisor table if:
- the numbers in the $i$-th row are exactly all the divisors of some natural number $r_i$,
- the numbers in the $j$-th column are exactly all the divisors of some natural number $c_j$,
- $r_i \ne r_j$ for every $i \ne j$.

A prime number $p$ is given. Determine the smallest natural number $n$, divisible by $p$, such that there exists an $n \times n$ divisor table, or prove that such $n$ does not exist.

Proposed by Pavle Martinović

c^a + a = 2^b

by Havu, May 10, 2025, 4:12 AM

Reflected point lies on radical axis

by Mahdi_Mashayekhi, Apr 19, 2025, 11:01 AM

Given is an acute and scalene triangle $ABC$ with circumcenter $O$. $BO$ and $CO$ intersect the altitude from $A$ to $BC$ at points $P$ and $Q$ respectively. $X$ is the circumcenter of triangle $OPQ$ and $O'$ is the reflection of $O$ over $BC$. $Y$ is the second intersection of circumcircles of triangles $BXP$ and $CXQ$. Show that $X,Y,O'$ are collinear.
This post has been edited 1 time. Last edited by Mahdi_Mashayekhi, Apr 19, 2025, 11:25 AM

Inequality

by SunnyEvan, Apr 1, 2025, 9:54 AM

Let $a$, $b$, $c$ be non-negative real numbers, no two of which are zero. Prove that :
$$ \sum \frac{3ab-2bc+3ca}{3b^2+bc+3c^2} \geq \frac{12}{7}$$

2- player game on a strip of n squares with two game pieces

by parmenides51, Mar 26, 2024, 3:48 PM

Alice and Bob play a game on a strip of $n \ge  3$ squares with two game pieces. At the beginning, Alice’s piece is on the first square while Bob’s piece is on the last square. The figure shows the starting position for a strip of $ n = 7$ squares.
https://cdn.artofproblemsolving.com/attachments/1/7/c636115180fd624cbeec0c6adda31b4b89ed60.png
The players alternate. In each move, they advance their own game piece by one or two squares in the direction of the opponent’s piece. The piece has to land on an empty square without jumping over the opponent’s piece. Alice makes the first move with her own piece. If a player cannot move, they lose.

For which $n$ can Bob ensure a win no matter how Alice plays?
For which $n$ can Alice ensure a win no matter how Bob plays?

(Karl Czakler)
This post has been edited 2 times. Last edited by parmenides51, Mar 26, 2024, 3:50 PM

Polynomial Application Sequences and GCDs

by pieater314159, Jun 19, 2019, 8:08 PM

Let $P(x)$ be a polynomial with integer coefficients such that $P(0)=1$, and let $c > 1$ be an integer. Define $x_0=0$ and $x_{i+1} = P(x_i)$ for all integers $i \ge 0$. Show that there are infinitely many positive integers $n$ such that $\gcd (x_n, n+c)=1$.

Proposed by Milan Haiman and Carl Schildkraut
This post has been edited 2 times. Last edited by pieater314159, Jun 27, 2019, 9:45 PM

equal segments on radiuses

by danepale, Apr 25, 2016, 6:39 PM

Let $ABC$ be an acute triangle with circumcenter $O$. Points $E$ and $F$ are chosen on segments $OB$ and $OC$ such that $BE = OF$. If $M$ is the midpoint of the arc $EOA$ and $N$ is the midpoint of the arc $AOF$, prove that $\sphericalangle ENO + \sphericalangle OMF = 2 \sphericalangle BAC$.

Incenters and Circles

by rkm0959, Nov 2, 2014, 9:24 AM

In a triangle $\triangle ABC$ with incenter $I$,
Let $D$ = $AI$ $\cap$ $BC$
$E$ = incenter of $\triangle ABD$
$F$ = incenter of $\triangle ACD$
$P$ = intersection of $\odot BCE$ and $\overline {ED}$
$Q$ = intersection of $\odot BCF$ and $\overline {FD}$
$M$ = midpoint of $\overline {BC}$

Prove that $D, M, P, Q$ concycle
This post has been edited 1 time. Last edited by rkm0959, Jun 7, 2015, 2:40 AM

This blog is about large numbers. There. Have I bored you yet?

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googology101
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  • 11 year bump

    by john0512, Dec 28, 2020, 3:03 AM

  • Sure.

    by googology101, Feb 12, 2009, 12:38 AM

  • me want contrib

    by gauss1181, Feb 11, 2009, 5:49 PM

  • Sorry, I ran out of time on the last shout...

    by googology101, Feb 8, 2009, 11:19 PM

  • and contrib?

    by james4l, Feb 8, 2009, 4:42 AM

  • I guess...

    by googology101, Feb 7, 2009, 11:49 PM

  • contrib please

    by james4l, Feb 7, 2009, 10:18 PM

  • Yeah, I noticed that too. I'll change it later, but there's a weird glitch for you. The top and left properties should be automatically set to 0 if position is set to absolute or fixed. Go Firefox!

    by googology101, Jan 21, 2009, 10:03 PM

  • i viewed this from ie and it looks like position fixed also ruins the left aligned so put left:0. nice submit buttons

    by Sephiroth, Jan 21, 2009, 5:32 AM

  • Use filter:alpha(opacity=80) to make it semitransparent in IE. And make sure you use -moz-opacity instead of opacity to make sure that older versions of Firefox will cooperate. And by the way, you're free to copy the code. The whole thing is at http://www.artofproblemsolving.com/Forum/templates/blogs/Hyperion/style/c1366.css

    by googology101, Jan 19, 2009, 9:50 PM

  • add filter: alpha(opacity=80) and opacity:0.8

    by Sephiroth, Jan 19, 2009, 3:51 AM

  • Could I use that code in my blog?

    by dysfunctionalequations, Jan 19, 2009, 1:51 AM

  • Watch out! position:fixed ruins the box's 100% width. Here's the code I used:

    #navigation_box {
    background-color: #005500 !important;
    border-bottom-style:solid !important;
    -moz-opacity:0.80;
    color:white !important;
    position:fixed !important;
    width:100%;
    padding-right:10px;
    }

    Don't overdo the opacity. 0.80 or 0.90 will do. Sorry, IE and Safari users, you aren't seeing it.

    by googology101, Jan 19, 2009, 1:26 AM

  • what do you mean by floating menus? like how he made navigation_box fixed? he used "#navigation_box{ position: fixed;}" i like how you made it opacity :)

    by Sephiroth, Jan 18, 2009, 4:45 AM

  • Floating menus? How do you do that?

    by dysfunctionalequations, Jan 18, 2009, 1:25 AM

  • Yup. I'm trying to post daily.

    by googology101, Jan 14, 2009, 12:05 AM

  • 3rd post!

    by 007math, Jan 13, 2009, 11:57 PM

  • Do you mean to this blog?

    by googology101, Jan 12, 2009, 9:30 PM

  • Can i be a contributor?

    by Wickedestjr, Jan 12, 2009, 5:49 PM

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