xooks rbo

by OronSH, Feb 28, 2024, 2:19 PM

antigonal conjugates :love:

Let $P$ be any point other than the orthocenter of $ABC$.
Its antigonal conjugate $Q$ is the reflection of $P$ across the center of the rectangular hyperbola through $A$, $B$, $C$, $P$.

i. We have $\measuredangle BPC = -\measuredangle BQC$ and so on.
ii. The isogonal conjugates of $P$ and $Q$ are inverses with respect to the circumcircle.

i. The Poncelet point of $A$ with respect to $\triangle BPC$ lies on the nine-point circle of $BPC,$ however it is also the Poncelet point of $P$ with respect to $\triangle ABC.$ Now, taking a homothety at $P$ with scale factor $2$ sends the nine-point circle of $BPC$ to the circle through $B,C,P'$ where $P'$ is the reflection of $P$ over $BC.$ Thus the antigonal conjugate of $P$ lies on this circle, so $\measuredangle BPC=-\measuredangle BP'C=-\measuredangle BQC.$

ii. Let $L$ be the center of the rectangular circumhyperbola $\mathcal H$ through $P,$ and let $\infty_1,\infty_2$ be the two points at infinity on the hyperbola. Since $(P,Q;\infty_1,\infty_2)_{\mathcal H}\stackrel L=(Q,P;\infty_1,\infty_2)_{\mathcal H}$ we see that the cross ratio is equal to $-1.$ Under isogonal conjugation, $\infty_1,\infty_2$ are sent to the intersections of the isogonal conjugate $\ell$ of the rectangular circumhyperbola with the circumcircle. Now $P,Q$ are sent to points on $\ell,$ but since isogonal conjugation preserves cross ratio (for example, take the pencil through $A$), they must be sent to inverses.
This post has been edited 2 times. Last edited by OronSH, Feb 29, 2024, 9:38 PM

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hyperbola so orz

by dolphinday, Feb 28, 2024, 3:14 PM

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xoron contrib

by ujulee, Feb 29, 2024, 12:44 AM

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orz $$ $$

by Inconsistent, Feb 29, 2024, 3:01 PM

susus

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  • wait why was a post by PEKKA deleted lol

    by lpieleanu, Yesterday at 7:21 PM

  • Hi! contrib pls? I literally have a math team named xooks lol

    by Cattus1221, Wednesday at 9:45 PM

  • exiters!!! xooks!! admits!!!!! now that's rizz!!!! xioooixiooix xoink!!!!

    by Inaaya, Wednesday at 2:31 PM

  • ???????????????????????????????

    by maxamc, Apr 14, 2025, 9:26 PM

  • someone is admitting (Kenneth Wu), on Kenneth Wus account

    by bjump, Apr 14, 2025, 5:23 PM

  • someone is trolling on my acc

    by KenWuMath, Apr 14, 2025, 2:45 PM

  • sus_rbo.

    by sus_rbo, Apr 11, 2025, 12:06 PM

  • wsg my second favorite borosillicate glass boron isotope orzon xoron oreo

    by Inaaya, Mar 30, 2025, 10:38 PM

  • wsg my second favorite borosillicate glass boron isotope orzon xoron oreo

    by Pengu14, Mar 30, 2025, 2:51 AM

  • wsg my favorite borosillicate glass boron isotope orzon xoron oreo

    by Inaaya, Mar 30, 2025, 2:14 AM

  • ORZ ORZ ORZ xooks

    by Mr.Sharkman, Mar 28, 2025, 12:39 AM

  • ohiorizzler1434

    by sixoneeight, Mar 23, 2025, 8:19 PM

  • exiters!!! xooks!! admits!!!!! now that's rizz!!!! xioooixiooix xoink!!!!

    by babyzombievillager, Mar 22, 2025, 1:40 AM

  • exiters!!! xooks!! admits!!!!! now that's rizz!!!! xioooixiooix xoink!!!!

    by Pengu14, Mar 21, 2025, 9:43 AM

  • exiters!!! xooks!! admits!!!!! now that's rizz!!!! xioooixiooix xoink!!!!

    by bjump, Mar 18, 2025, 5:04 PM

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