Some More (Basic) Properties of the configuration of orthic axis
by AlastorMoody, Jan 28, 2019, 10:11 PM
Here are some more basic properties!
Define:


Credits to math_pi_rate for giving such amazing names


Pre Eliminaries
is defined as 
is defined as 
Note: This implies that
lie on the same circle
Also Define:
as the Radical Center of 
Similarly, define
and 
Lemma 1:
lie on the same line (This line is known as the orthic axis)
Proof: Note,
, hence,
is the center of perspectivity of
and
, applying Desargues' Theorem on perspective triangles
and
implies
lie on the same line 
Note(1): Infact the above proof follows from the fact that the Orthic Axis is defined as the Axis of Perspectivity of the orthic triangle and reference triangle
Note(2): Another way of defining the Orthic Axis, Let the reflections of
over
be
, Denote,
as the midpoints of
, then the polar of
WRT
is the Orthic Axis WRT 
Lemma 2:
is the diameter of 
Proof: Easy to see that
finishes the lemma 
Note: If
is the midpoint of
, then, 
Lemma 3: Let
be any point on
, and Let
and
, then, 
Proof: Let
and
, then,

Lemma 4: Let
intersect
at
, then
is isosceles triangle
Proof: It's Well-Known that
, then using (Lemma 3) and the fact that
is cyclic trapezoid
is isosceles 
Generalization(Lemma 3): Let
intersect
at
, then,
is the angle bisector of 
Proof: Follows from (Lemma 4)
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Main (Basic) Properties
Property 1:
is the foot of altitude from
in
OR (Restatement)
lies on 
Proof: Let
be the antipode of
WRT
, hence, it easily follows that
and then, Notice that
is the center of
,and finish off with Brokard's Theorem 
Consequence(1): From (Property 1), we can show that,
lies on 
Consequence(2): From (Property 1),
is a cyclic quadrilateral
Property 2: Let the reflections of
over
be
, Denote,
as the midpoints of
, then the polar of
WRT
is the Orthic Axis WRT 
Proof:(enhanced) Define:
and let a parallel line (
) to
through
intersect
at
, Let
, Applying (Lemma 4)
lies on the polar of
WRT
, also it is trivial to see that,
and the fact that
the polar of
WRT
and
are parallel, now take homothety(
) centered at
, such,
, then, it's clear that the polar of
WRT
will be the Orthic Axis WRT

Property 3: The Euler line WRT
is orthogonal to Orthic Axis WRT 
Proof: Notice that, if,
, then
, then Apply (Property 2),
the orthogonality 
Property 4:
lie on the same line
Proof: This follows from the definition of
combined with (Consequence(1) from Property(1)) 
Property 5: Let
, then,
lies on 
Proof: Let
be the antipode of
WRT
, Hence, from (Property 1),
, and then, it is easy to see,
and using the fact that

Property 6: Finding Some Cyclic Quadrilaterals!
(1) Points
lie on a circle
(2) Points
lie on a circle
(3) Points
lie on a circle
Note: Adding the
(
Humpty Point),
and 
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And....of course, there are many more properties that I found, But I haven't listed them over here, because many of them are pretty trivial and kinda useless(not so interesting), So I will limit these properties so as not make this post boring
Define:


Credits to math_pi_rate for giving such amazing names


Pre Eliminaries






Note: This implies that

Also Define:


Similarly, define


Lemma 1:

Proof: Note,








Note(1): Infact the above proof follows from the fact that the Orthic Axis is defined as the Axis of Perspectivity of the orthic triangle and reference triangle
Note(2): Another way of defining the Orthic Axis, Let the reflections of








Lemma 2:


Proof: Easy to see that


Note: If



Lemma 3: Let





Proof: Let








Lemma 4: Let




Proof: It's Well-Known that





Generalization(Lemma 3): Let





Proof: Follows from (Lemma 4)

________________________________________________________________________________________________________________________________________________________________________________________________________________
Main (Basic) Properties
Property 1:





Proof: Let







Consequence(1): From (Property 1), we can show that,


Consequence(2): From (Property 1),

Property 2: Let the reflections of








Proof:(enhanced) Define:




























Property 3: The Euler line WRT


Proof: Notice that, if,




Property 4:

Proof: This follows from the definition of


Property 5: Let



Proof: Let









Property 6: Finding Some Cyclic Quadrilaterals!
(1) Points

(2) Points

(3) Points

Note: Adding the





_____________________________________________________________________________________________________________________________________________________________________________________________________________
And....of course, there are many more properties that I found, But I haven't listed them over here, because many of them are pretty trivial and kinda useless(not so interesting), So I will limit these properties so as not make this post boring
This post has been edited 47 times. Last edited by AlastorMoody, Feb 5, 2019, 2:12 PM