[/quote]
,
to 
.
)
.
and 
,
is not less than the area of 
,
inequalities, these given comparisons satisfy the following three constraints:
and 
,
and 
respectively, then the sum of elements of the union 
is greater than that of 
.
that satisfies all these conditions?
be an acute triangle. Denote by 
the foot of the perpendicular line drawn from the point 
to the side 
,
the midpoint of 
the orthocenter of 
be the point of intersection of the circumcircle 
of the triangle 
,
be the point of intersection (other than 
)
and the circle 
must hold.
the length of the line segment 
such that 
(where 
)
that satisfies 
for all 
is the function obtained by composing 
times, that is, 
)
,
be the projection from 
past 
.
be on the perpendicular bisector of 
such that 
are on the same side of ![\[\frac12\angle ALE=1.4\angle ABE+3.4\angle ACE-558^\circ\]](http://latex.artofproblemsolving.com/c/6/3/c63eeb053f1fa8a29bef93516814ae121382219e.png)
Let the reflection of 
and 
and 
,
and 
such that 
.
and 
intersect the circumcircles of 
and 
at 
and 
,
and 
intersect 
and 
at 
.
.
sastifying 
such that the relation ![\[|z^{2n}+z^nw^n+w^{2n} | = 2^{2n}+2^n+1 \]](http://latex.artofproblemsolving.com/1/2/2/1229a609403904449c447225094b3d97e063efd4.png)
holds for all positive integers 
,
,
of positive integers 
such that 
.
denotes component-wise function multiplication)
and 
Prove that
distinct points 
connected if the line 
points from 
such that there exists a set 
is connected with exactly 
other points from 
Y by Adventure10, Mango247
Let 
be a triangle right in 
. Construct a point 
on the hypotenuse 
such that if 
is the foot of the perpendicular drawn from to side 
, then the area of the square of side 
is equal to the area of the rectangle of sides 
and 
. Show construction steps.
be a triangle right in 
. Construct a point 
on the hypotenuse 
such that if 
is the foot of the perpendicular drawn from to side 
, then the area of the square of side 
is equal to the area of the rectangle of sides 
and 
. Show construction steps.This post has been edited 1 time. Last edited by parmenides51, May 28, 2024, 3:08 PM
is a parallelogram and 
.
the symmetric of 
i.e 
is cyclic more since 
then 
. let 
the symmetric of 
,remark that it 's easy to show that 
the center of 
is on the intersection of 
and the 
through which cuts 
