Difference between revisions of "2021 JMPSC Sprint Problems/Problem 15"

Revision as of 19:53, 7 September 2021

Problem

Find the last two digits of $10^{10}-5^{10}.$

Solution

Note that $10^{10}\equiv0\pmod{100}$ and $5^{10}\equiv25\pmod{100}$ .

$0-25=-25$ . $-25\equiv\boxed{75}\pmod{100}$

Solution 2

By multiplying out several powers of $5$ , we can observe that the last $2$ digits are always $25$ (with the exception of $5^n$ where $n \le 1$ ). Also, $10^{10}$ ends with several zeros, so the answer is $100...00 - 25 = 99...99 - 24 = 999...75$ .

~Mathdreams

Solution 3

$100^{10} \equiv 0 \mod 100$ $5^{10} \equiv 25 \mod 100$ Therefore, the answer is $75$

- kante314 -

@@ Line 9: / Line 9: @@
 == Solution 2 ==
-By multiplying out several powers of <math>5</math>, we can observe that the last <math>2</math> digits are always <math>25</math> (with the exception of <math>5^n</math> where <math>n \le 1</math>). Also, <math>10^10</math> ends with several zeros, so the answer is <math>100...00 - 25 = 99...99 - 24 = 999...75</math>.
+By multiplying out several powers of <math>5</math>, we can observe that the last <math>2</math> digits are always <math>25</math> (with the exception of <math>5^n</math> where <math>n \le 1</math>). Also, <math>10^{10}</math> ends with several zeros, so the answer is <math>100...00 - 25 = 99...99 - 24 = 999...75</math>.
 ~Mathdreams

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