Difference between revisions of "User:Tonypr"
Line 4: | Line 4: | ||
Proof <math>2=1</math>: | Proof <math>2=1</math>: | ||
− | |||
− | + | Suppose that <math>a=b</math> | |
− | + | <math> | |
− | + | \begin{eqnarray*} | |
− | + | a&=&b\ | |
− | + | a^2&=&ab\ | |
− | + | a^2-b^2&=&ab-b^2\ | |
− | + | (a+b)(a-b)&=&b(a-b)\ | |
− | + | a+b&=&b\ | |
− | + | b+b&=&b\ | |
− | + | 2b&=&b\ | |
− | + | 2&=&1 | |
− | + | \end{eqnarray*} | |
+ | </math> |
Revision as of 22:39, 23 May 2009
Awesome math solver from Puerto Rico, soon to be International Math Olympiad.
Proof :
Suppose that
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