Difference between revisions of "Mock AIME 2 2006-2007 Problems/Problem 9"

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==See Also==
 
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{{Mock AIME box|year=2006-2007|n=2|num-b=8|num-a=10}}
*[[Mock AIME 2 2006-2007 Problems/Problem 8 | Previous Problem]]
 
 
 
*[[Mock AIME 2 2006-2007 Problems/Problem 10 | Next Problem]]
 
 
 
*[[Mock AIME 2 2006-2007]]
 

Revision as of 09:52, 4 April 2012

Problem

In right triangle $ABC,$ $\angle C=90^\circ.$ Cevians $AX$ and $BY$ intersect at $P$ and are drawn to $BC$ and $AC$ respectively such that $\frac{BX}{CX}=\frac23$ and $\frac{AY}{CY}=\sqrt 3.$ If $\tan \angle APB= \frac{a+b\sqrt{c}}{d},$ where $a,b,$ and $d$ are relatively prime and $c$ has no perfect square divisors excluding $1,$ find $a+b+c+d.$

Solution

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See Also

Mock AIME 2 2006-2007 (Problems, Source)
Preceded by
Problem 8
Followed by
Problem 10
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