2021 Fall AMC 12B Problems/Problem 9
Problem
Triangle is equilateral with side length
. Suppose that
is the center of the inscribed
circle of this triangle. What is the area of the circle passing through
,
, and
?
Solution 1 (Cosine Rule)
Construct the circle that passes through ,
, and
, centered at
.
Then connect , and notice that
is the perpendicular bisector of
. Let the intersection of
with
be
.
Also notice that and
are the angle bisectors of angle $\angleBAC$ (Error compiling LaTeX. Unknown error_msg) and $\angleBCA$ (Error compiling LaTeX. Unknown error_msg) respectively. We then deduce
.
Consider another point on Circle
opposite to point
.
As an inscribed quadrilateral of Circle
, $\angleAMC=180^\circ-120^\circ=60^\circ$ (Error compiling LaTeX. Unknown error_msg).
Afterward, deduce that $\angleAXC=2·\angleAMC=120^\circ$ (Error compiling LaTeX. Unknown error_msg).
By the Cosine Rule, we have the equation: (where is the radius of circle
)
The area is therefore .
~Wilhelm Z