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1994 AHSME Problems/Problem 12

Revision as of 21:06, 27 June 2014 by TheMaskedMagician (talk | contribs) (Created page with "==Problem== If <math>i^2=-1</math>, then <math>(i-i^{-1})^{-1}=</math> <math> \textbf{(A)}\ 0 \qquad\textbf{(B)}\ -2i \qquad\textbf{(C)}\ 2i \qquad\textbf{(D)}\ -\frac{i}{2} \qq...")
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Problem

If $i^2=-1$, then $(i-i^{-1})^{-1}=$

$\textbf{(A)}\ 0 \qquad\textbf{(B)}\ -2i \qquad\textbf{(C)}\ 2i \qquad\textbf{(D)}\ -\frac{i}{2} \qquad\textbf{(E)}\ \frac{i}{2}$

Solution

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