1963 TMTA High School Algebra I Contest Problem 25
Revision as of 10:04, 2 February 2021 by Coolmath34 (talk | contribs) (Created page with "== Problem == If <math>\sqrt{5}=2.236,</math> the value of <math>\frac{1+\sqrt{5}}{3-2\sqrt{5}}</math> to the nearest hundredth is: <math>\text{(A)} \quad -2.25 \quad \text{(...")
Problem
If 
the value of 
to the nearest hundredth is:
Solution
Simplify the expression first:
![\[\frac{1+\sqrt{5}}{3-2\sqrt{5}} \cdot \frac{3+2\sqrt{5}}{3+2\sqrt{5}}=\frac{3+3\sqrt{5}+2\sqrt{5}+10}{-17}=\frac{-13+5\sqrt{5}}{11}\]](http://latex.artofproblemsolving.com/b/6/0/b60c3c3e49534cf2ecfdf76c9a9b5b15858a3543.png)
Then we can use our approximation 
We see that this is closest to 
See Also
| 1963 TMTA High School Mathematics Contests (Problems) | ||
| Preceded by Problem 24 |
TMTA High School Mathematics Contest Past Problems/Solutions | Followed by Problem 26 |
