User:R31415

$e^ i\pi=-1$ Which means that i^i equals $(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2$ (e^i*e^\pi*e^1/2)^i= e^-\pi/2$ <dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>