AoPS Wiki talk:Problem of the Day/September 12, 2011
Revision as of 15:37, 12 September 2011 by Negativebplusorminus (talk | contribs) (Created page with "Dropping an altitude, we see that it has length <math>3\sqrt{2}</math> by the 45-45-90 triangle. Thus, the midsegment must have length <math>5\sqrt{2}</math>. Dropping altitude...")
Dropping an altitude, we see that it has length 
by the 45-45-90 triangle. Thus, the midsegment must have length 
. Dropping altitudes from B and C, we see that the sum of the bases is 
, and thus 
and 
.
