Difference between revisions of "1998 CEMC Gauss (Grade 7) Problems/Problem 4"

Revision as of 18:25, 12 May 2024

Jean writes five tests and achieves the marks shown on the graph. What is her average mark on these five tests?

[insert bar graph with 5 bars: 80, 70, 60, 90, 80]

$\text{(A)}\ 74 \qquad \text{(B)}\ 76 \qquad \text{(C)}\ 70 \qquad \text{(D)}\ 64 \qquad \text{(E)}\ 79$

The average of the $5$ tests is $\frac{80+70+60+90+70}{5} = \boxed{74}.$

The answer is $\text{(A)}$ .

-edited by coolmath34

When 80 + 70 + 60 + 90 + 80 added together the total is 380. Next 380 ÷ 5 = 76

+___ 380 ÷ 5 = 76 Therefore when 80+70+60+90+80 are added together the total is 380 ÷ 5 = 76 so (B) 76 is correct answer.

-edited by De-math-wiz

@@ Line 12: / Line 12: @@
 -edited by coolmath34
+== Solution ==
+When 80 + 70 + 60 + 90 + 80 added together the total is 380.
+Next 380 ÷ 5 = 76
++___
+÷ 5 = 76
+Therefore when 80+70+60+90+80 are added together the total is 380 ÷ 5 = 76 so (B)  76 is correct answer.
+-edited by De-math-wiz