Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 5, 2011"
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==Problem== | ==Problem== | ||
{{:AoPSWiki:Problem of the Day/June 5, 2011}} | {{:AoPSWiki:Problem of the Day/June 5, 2011}} | ||
− | == | + | ==Solution== |
− | <math>\boxed{4}</math> | + | |
+ | First, let's simply the expression <math> f(g(7+-3)+3) </math>. We have <math>f(g(7+-3)+3) = f(g(4)+3).</math> We know that <math>g(x)=4x-6</math>. | ||
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+ | That implies that <math>g(4)=4(4)-6=10</math>. Now we know that <math>f(g(7+-3)+3) = f(g(4)+3) = f(10+3) = f(13) = \frac{13}{2} - \frac{5}{2} = \boxed{4}</math>. |
Latest revision as of 21:52, 4 June 2011
Problem
AoPSWiki:Problem of the Day/June 5, 2011
Solution
First, let's simply the expression . We have We know that .
That implies that . Now we know that .