Difference between revisions of "1955 AHSME Problems/Problem 33"
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<math> \textbf{(A)}\ \text{6 hr.}\qquad\textbf{(B)}\ \text{6 hr. 43-7/11 min.}\qquad\textbf{(C)}\ \text{5 hr. 16-4/11 min.}\qquad\textbf{(D)}\ \text{6 hr. 30 min.}\qquad\textbf{(E)}\ \text{none of these} </math> | <math> \textbf{(A)}\ \text{6 hr.}\qquad\textbf{(B)}\ \text{6 hr. 43-7/11 min.}\qquad\textbf{(C)}\ \text{5 hr. 16-4/11 min.}\qquad\textbf{(D)}\ \text{6 hr. 30 min.}\qquad\textbf{(E)}\ \text{none of these} </math> | ||
| − | [[1955 AHSME Problems | + | ==Solution== |
| + | |||
| + | ==See Also== | ||
| + | In order to get back to the problem set, click [[1955 AHSME Problems|here]] | ||
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| + | {{MAA Notice}} | ||
Latest revision as of 20:23, 4 October 2023
Problem 33
Henry starts a trip when the hands of the clock are together between 
a.m. and 
a.m.
He arrives at his destination between 
p.m. and 
p.m. when the hands of the clock are exactly 
apart. The trip takes:
Solution
See Also
In order to get back to the problem set, click here
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
