1969 Canadian MO Problems/Problem 10
Problem
Let be the right-angled isosceles triangle whose equal sides have length 1. is a point on the hypotenuse, and the feet of the perpendiculars from to the other sides are and . Consider the areas of the triangles and , and the area of the rectangle . Prove that regardless of how is chosen, the largest of these three areas is at least .
Solution
Let Because triangles and both contain a right angle and a angle, they are isosceles right triangles. Hence, and
Now let's consider when or else one of triangles and will automatically have area greater than In this case, Therefore, one of these three figures will always have area greater than regardless of where is chosen.
1969 Canadian MO (Problems) | ||
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