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- MP('I', (8,-8), (0,0)); ...{(D) } II,\,\textrm{ by }\,8\pi\qquad \textbf{(E) } II,\,\textrm{ by }\,10\pi </math>3 KB (424 words) - 09:14, 17 December 2021
- <center><cmath>p(2009 + 9002\pi i) = p(2009) = p(9002) = 0</cmath></center> ...textbf{(B)}\ 6\qquad \textbf{(C)}\ 8\qquad \textbf{(D)}\ 10\qquad \textbf{(E)}\ 12</math>2 KB (322 words) - 09:25, 29 July 2020
- ...in the given square. If <math>r</math> is the ratio of the area of circle I to that of circle II, then <math>r</math> equals: ...B) } 2 \quad \text{(C) } \sqrt{3} \quad \text{(D) } 2\sqrt{2} \quad \text{(E) } 2\sqrt{3}</math>1 KB (191 words) - 21:09, 14 January 2018
- ...c}</math> on circle <math>II</math>, the ratio of the area of circle <math>I</math> to that of circle <math>II</math> is: \text{(E) } \text{none of these}</math>1 KB (230 words) - 19:16, 17 July 2024
- \text{(E) } 16</math> This equation is <math>r^6e^{6\theta i}=2^6e^{(\pi\pm 2k\pi) i}</math>. Solving in the usual way, <math>r=2</math> and <math>\theta\in\{\p798 bytes (133 words) - 12:17, 4 February 2016
- ...e <math>A</math> with the circumcircle of <math>ABC</math>. The line <math>PI</math> intersects for the second time the circumcircle of <math>ABC</math> ...h> intersect the circumcircle of <math>ABC</math> at <math>D</math>, <math>E</math> respectively. It is well known that <math>PDIE</math> is a parallelo1 KB (191 words) - 03:59, 26 March 2024