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• 1977 Canadian MO Problems
  MP("1 cm",(.5,.04),S);MP("3 cm",(.5,1.35),NE);
  3 KB (560 words) - 19:23, 10 March 2015
• KGS math club
  |2016-12-04 |2016-12-04
  22 KB (3,358 words) - 15:17, 18 July 2017
• 2008 IMO Problems/Problem 5
  --[[User:Vbarzov|Vbarzov]] 03:04, 5 September 2008 (UTC)
  4 KB (677 words) - 01:10, 19 November 2023
• API:Product List
  |style="padding-right:20px"|978-1-934124-04-8
  3 KB (421 words) - 14:45, 28 May 2009
• KGS math club/solution 11 10
  --[[User:Cyryts|Cyryts]] 04:47, 12 January 2012 (EST)
  108 bytes (14 words) - 05:47, 12 January 2012
• 2012 AIME I Problems/Problem 1
  ...th>bc</math> and <math>ba</math> must be divisible by 4. So <math>bc = 00, 04, 08, 12, 16, ... , 92, 96</math> and so must <math>ba</math> for each two d
  3 KB (486 words) - 03:59, 21 January 2023
• KGS math club/solution 11 15
  D239500800 (06/04/12 17:21):
  630 bytes (106 words) - 06:41, 8 April 2012
• 2014 AMC 10A Problems/Problem 20
  ...e in the form <math>7</math>, <math>k-2</math> <math>1</math>'s, and <math>04</math>. We want to make the numbers sum to 1000, so <math>7+4+(k-2) = 1000<
  3 KB (534 words) - 21:30, 9 May 2023
• 1977 Canadian MO Problems/Problem 5
  MP("1 cm",(.5,.04),S);MP("3 cm",(.5,1.35),NE);
  889 bytes (136 words) - 15:53, 7 October 2014
• 2015 AMC 12A Problems/Problem 14
  Video starts at 1:04, uses the above solution: https://www.youtube.com/watch?v=OJyWHzjiu2A&t=44s
  1 KB (167 words) - 04:12, 13 November 2022
• 2018 AIME I Problems/Problem 1
  http://artofproblemsolving.com/wiki/index.php?title=File:Screen_Shot_2018-04-30_at_8.15.00_PM.png#file [[File:Screen Shot 2018-04-30 at 8.15.00 PM.png|thumb|240px]]
  10 KB (1,670 words) - 16:38, 15 January 2024
• 2019 AIME II Problems/Problem 4
  04 => 2^2*3^0*5^0 ___ term :4*4+3*3+3*3+2*2+3*3+1*1+1*1+1*1=16+09+09+04+09+01+01+01=50
  19 KB (2,942 words) - 21:22, 21 January 2024
• Euler's Totient Theorem Problem 1 Solution
  ...e <math> \phi(100)=40 </math>, this reduces to <math> 7^1-3^1\equiv \boxed{04}\pmod{100} </math>. -BorealBear
  272 bytes (35 words) - 17:33, 21 March 2023
• 2021 JMPSC Sprint Problems/Problem 19
  ...hat <math>T=0</math>. Then we have <math>M:AT=4:50</math> and <math>A:TM=5:04</math>. Checking, the times are indeed 14 minutes apart! We want <math>A \t
  2 KB (265 words) - 17:15, 11 July 2021
• 2022 AMC 10A Problems/Problem 24
  ...igits} & \boldsymbol{01} & \boldsymbol{02} & \boldsymbol{03} & \boldsymbol{04} & \textbf{Row's Count} \\ [0.5ex]
  12 KB (1,898 words) - 12:48, 26 March 2024
• 2023 AMC 12B Problems/Problem 16
  01 & 02 & 03 & 04 & 05 & \textcolor{red}{\boxed{06}} \\
  8 KB (1,317 words) - 21:51, 5 March 2024