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  • ...e trying to get <math>a^2+b^2-2f^2+2de</math> on the LHS, because then the RHS would be <math>c^2</math>.
    6 KB (1,003 words) - 23:02, 19 May 2024
  • ...>, to get <math>r^ne^{ni\theta} = e^{2\pi ik}</math>. The magnitude of the RHS is 1, making <math>r^n=1\Rightarrow r=1</math> (magnitude is always express ...ta} </math>, we see that <math> r^n = 1</math>, since the magnitude of the RHS of <math> x^n=1 </math> is 1, and for two complex numbers to be equal, both
    3 KB (558 words) - 20:36, 11 December 2011
  • We can see that the LHS is <math>cis(n(90^{\circ}-t))</math>, and the RHS is <math>cis(90^{\circ}-nt)</math> So, <math>n(90-t) \equiv 90-nt \mod 360<
    6 KB (1,154 words) - 02:30, 11 January 2024
  • ...ath>, we see that <math>a_{k}a_{k+1} = 37\cdot 72 - 3k</math>. Setting the RHS of this equation equal to <math>3</math>, we find that <math>m</math> must
    3 KB (499 words) - 17:52, 21 November 2022
  • The leading coefficient of the RHS is <math>-1</math> because the leading coefficient of the LHS is <math>-1</
    6 KB (1,051 words) - 18:35, 1 August 2024
  • ...ike <math>1,-1,-1,-1,1</math> we find the LHS to be <math>5</math> and the RHS to be <math>1.</math> What happened? There were more negatives than positiv Straight off, we notice that the RHS must be greater than or equal to 19, because an absolute value only gives n
    2 KB (394 words) - 09:21, 27 January 2024
  • ...this equation matches the LHS equation that I said was important. So, the RHS of both equations are equal, and thus <math>145k-2 = k+34</math> We move al
    5 KB (766 words) - 23:46, 8 November 2024
  • ...ath>du</math> and <math>dv</math> as <math>v</math> in the integral on the RHS, <math>u</math> should be chosen such that it has an "easy" (or "easier") [
    1 KB (235 words) - 16:01, 11 March 2022
  • Subtracting the LHS from the RHS,
    1 KB (214 words) - 14:06, 18 October 2015
  • Since <math> 1+2+...+n = \frac{n(n+1)}{2} </math> we may substitute the [[RHS]] in the above [[fraction]]. So the problem asks us for how many [[positive
    1 KB (220 words) - 11:54, 14 December 2021
  • ...tions we will have a total of 4 of each variable on the [[LHS]]. On the [[RHS]] we will have <math>4+8+12+16+20 = 60</math>. Thus <center><math> 4(a+b+c ...d equation leaves <math>d</math> on the LHS and <math>15-8=7</math> on the RHS. And thus we continue on in this way to find that <math>(a,b,c,d,e)=(-5,-1
    5 KB (786 words) - 15:11, 7 December 2024
  • ...ine <math>\theta</math> such that <math> x = \tan{\theta}</math>. Then the RHS becomes
    2 KB (312 words) - 09:38, 4 April 2012
  • Adding LHS of <math>(1)</math> with RHS of <math>(2)</math> (and vice-versa), we get We know that the RHS is <math>2007</math> by previous work. Therefore, <math>b_{n+1}b_{n-1}-b_n^
    13 KB (2,214 words) - 16:39, 28 November 2024
  • We must prove that the RHS of this equation is less than or equal to <math>a^2 + b^2 + c^2</math>. and the RHS becomes <math>4\sqrt{3}\sqrt{(x+y+z)xyz}</math> If we use Heron's formula.
    4 KB (849 words) - 06:29, 30 July 2024
  • Obviously, <math>\deg Q = 2</math> and the RHS has roots <math>1, 2, 3.</math> Thus, the only requirement is that <math>Q<
    5 KB (848 words) - 22:42, 29 September 2024
  • As a [[function]] of <math>h_x</math>, the [[RHS]] of this equation is strictly decreasing, so it takes each value in its [[
    6 KB (994 words) - 12:40, 3 December 2024
  • After cancelling the <math> a^{\frac{14}{3}}</math> term, we apply AM-GM to RHS and obtain
    7 KB (1,194 words) - 05:11, 22 October 2024
  • ...nd the sum of the imaginary parts of complex conjugates is zero. Hence the RHS is zero.
    3 KB (517 words) - 13:13, 5 September 2021
  • ...\equiv 1\pmod{3}</math>: Then the LHS is <math>1\pmod{3}</math>, while the RHS isn't. ...\equiv 2\pmod{3}</math>: Then the LHS is <math>1\pmod{3}</math>, while the RHS isn't.
    1 KB (250 words) - 23:38, 27 October 2015
  • ...gets divided out (leaving a <math>5</math> for multiplication), and on the RHS, the <math>5</math> gets divided out (leaving a <math>3</math> for multipli
    4 KB (562 words) - 17:49, 8 November 2020

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