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• 2003 AMC 10A Problems/Problem 14
  ...+3=12 \Rightarrow \boxed{\mathrm{(A)}\ 12}</math> ~ MathGenius_ (Edited by Sophia866)
  2 KB (336 words) - 15:49, 19 August 2023
• 2003 AMC 12A Problems/Problem 8
  ...answer is <math>\frac{6}{12} = \boxed{\mathrm{(E)}\ \frac{1}{2}}</math>. ~Sophia866
  2 KB (326 words) - 15:40, 19 August 2023
• 2003 AMC 12A Problems/Problem 13
  ...ath> work. Therefore, the answer is <math>\boxed{\mathrm{(E)}\ 6}</math>. ~Sophia866
  3 KB (407 words) - 15:43, 19 August 2023