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• 2015 AMC 8 Problems/Problem 21
  ...12</math>. Therefore, the answer is <math>\boxed{\textbf{(C)}~12}</math>. ~strongstephen
  3 KB (471 words) - 19:36, 17 January 2024
• 2015 AMC 8 Problems/Problem 20
  ~strongstephen
  5 KB (912 words) - 17:55, 23 October 2024
• 2018 AMC 8 Problems/Problem 11
  ...1}{5} = \boxed{\frac{7}{15}}</math> , or <math>\boxed{\textbf{C}}</math>. ~strongstephen
  3 KB (546 words) - 08:08, 10 April 2024