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• 2021 AIME I Problems/Problem 11
  ...sect at <math>E,</math> and let <math>\angle AEB=\theta.</math> It follows that <math>\angle CED=\theta</math> and <math>\angle BEC=\angle DEA=180^\circ-\t Note that <math>\cos(180^\circ-\theta)=-\cos\theta</math> holds for all <math>\theta.
  16 KB (2,648 words) - 01:28, 28 November 2024
• 2020 AMC 8 Problems/Problem 23
  ...ards are to be given to three students. Each student will receive at least one award. In how many different ways can the awards be distributed? ...ceive <math>4</math> or <math>5</math> awards because this would mean that one of the other students receives no awards. Thus, each student must receive e
  5 KB (867 words) - 12:13, 20 December 2024