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- 33 bytes (4 words) - 23:02, 6 November 2020
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- ..., 0), let B be (0, 9), and let F be (12, 3). You can then use the shoelace theorem to find the area of DBF, which is 42. <math> \frac {42}{96} = \boxed{\frac ==Solution 6 (Wooga Looga Theorem)==6 KB (905 words) - 11:05, 15 December 2024
- ==Generalized Wooga Looga Theorem (The Devil's Triangle)== ...y. The Generalized Wooga Looga Theorem (Gwoologth) or the Devil's Triangle Theorem states that if <math>\frac{BD}{CD}=r, \frac{CE}{AE}=s</math> and <math>\fra3 KB (582 words) - 17:05, 23 March 2024
- [[Wooga Looga Theorem]] [[Georgeooga-Harryooga Theorem]]1,005 bytes (92 words) - 22:11, 17 January 2021
- ...not an alternative to the [[Georgeooga-Harryooga Theorem]] because in this theorem the only situation that is not allowed is that all <math>k</math> objects a By the Arrangement Restriction Theorem, we get <math>\frac{8! - (8 - 3 + 1)!3!}{2} = \boxed{18000}</math> because2 KB (269 words) - 23:16, 20 December 2020