Talk:Trivial Inequality

I'm just wondering if the proof presented is 'rigorous'... I'll need a 3rd reader to confirm this.--10000th User 16:47, 22 November 2007 (EST)

I think it is most certainly rigorous.--1=2 9:08, 23 November 2007 (EST)

There is a constructive proof presented in Rudin's book Principles of Mathematical Analysis that does not use the method of contradiction. But, the proof itself is quite lengthy and depends on several basic propositions derived from the field axioms. Anyways, thank you so much 1=2.--10000th User 11:58, 23 November 2007 (EST)

I also think the proof is rigorous. ~Ddk001