View source for Solution to Principle of Insufficient Reason Introductory Problem 1

==Problem 1==
<math>\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}</math>
==Olympaid problem==
Principle of Insufficient Reason <math>\implies</math> the max of <math>e</math> is achieved when <math>a=b=c=d</math> so <cmath>4a+e=8</cmath> <cmath>4a^2+e^2=16</cmath> <cmath>\implies e=\frac{16}{5}</cmath>