Japanese Theorem

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The Japanese theorem exists for both cyclic quadrilaterals and cyclic polygons.

Japanese theorem for cyclic quadrilaterals

Definition

The Japanese theorem for cyclic quadrilaterals states that for a cyclic quadrilateral $ABCD$ and incenters $M_1$, $M_2$, $M_3$, $M_4$ of triangles $\triangle ABD$, $\triangle ABC$, $\triangle BCD$, $\triangle ACD$ the quadrilateral $M_1M_2M_3M_4$ is a rectangle.


Japanese theorem quadrilaterals.png

Proof

From $\triangle ABC$, we can see that

$\angle BM_2C = 90^{\circ} + \frac{1}{2} \angle CAB$

Similarly, from $\triangle BCD$ we have

$\angle BM_3C = 90^{\circ} + \frac{1}{2} \angle CDB$

Since $ABCD$ is cyclic, therefore $\angle CDB = \angle CAB$, which means that

$\angle BM_2C = \angle BM_3C$

From this, it follows that $BM_2M_3C$ is cyclic. This means that

$\angle BCM_3 + \angle BM_2M_3 = 180^{\circ}$

By symmetry, we can also derive

$\angle BAM_1 + \angle BM_2M_1 = 180^{\circ}$

Adding these equations up, we get

$\angle BAM_1 + \angle BCM_3 + \angle BM_2M_1 + \angle BM_2M_3 = 360^{\circ}$

$\Rightarrow \angle BM_2M_1 + \angle BM_2M_3 = 360^{\circ} - \angle BAM_1 - \angle BCM_3 = 360^{\circ} - \frac{1}{2} \left(\angle CAB + \angle CDB \right)$

Which implies

$M_1M_2M_3 = 90^{\circ}$

And other angles similarly.

$Q.E.D.$


Japanese theorem for cyclic polygons

Definition

The Japanese theorem for cyclic polygons states that for any triangulated cyclic polygon, the sum of the inradii of the triangles is constant.