Difference between revisions of "Power set"
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− | Note that this proof does not rely upon either the [[ | + | Note that this proof does not rely upon either the [[Continuum Hypothesis]] or the [[Axiom of Choice]]. It is a good example of a [[diagonal argument]], a method pioneered by the mathematician [[Georg Cantor]]. |
==See Also== | ==See Also== |
Revision as of 12:14, 7 September 2006
The power set of a given set is the set of all subsets of that set.
Contents
[hide]Examples
The empty set has only one subset, itself. Thus .
A set with a single element has two subsets, the empty set and the entire set. Thus .
A set with two elements has four subsets, and .
Similarly, for any finite set with elements, the power set has elements.
Size comparison
Note that for any nonnegative integer , and so for any finite set , (where absolute value signs here denote the cardinality of a set). The analogous result is also true for infinite sets (and thus for all sets): for any set , the cardinality of the power set is strictly larger than the cardinality of the set itself.
Proof
There is a natural injection taking , so . Suppose for the sake of contradiction that . Then there is a bijection . Let be defined by . Then and since is a bijection, .
Now, note that by definition if and only if , so if and only if . This is a clear contradiction. Thus the bijection cannot really exist and so , as desired.
Note that this proof does not rely upon either the Continuum Hypothesis or the Axiom of Choice. It is a good example of a diagonal argument, a method pioneered by the mathematician Georg Cantor.
See Also
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