Difference between revisions of "2019 AMC 12B Problems/Problem 2"
(→Solution) |
|||
| Line 2: | Line 2: | ||
==Solution== | ==Solution== | ||
| + | |||
| + | answer should be 27 | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2019|ab=B|num-b=1|num-a=3}} | {{AMC12 box|year=2019|ab=B|num-b=1|num-a=3}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 11:45, 14 February 2019
Problem
Solution
answer should be 27
See Also
| 2019 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
