Difference between revisions of "2019 AMC 12B Problems/Problem 5"
(→Solution) |
(→Solution) |
||
Line 3: | Line 3: | ||
==Solution== | ==Solution== | ||
− | n = 18 | + | n = 18 (SuperWill) |
==See Also== | ==See Also== | ||
{{AMC12 box|year=2019|ab=B|num-b=4|num-a=6}} | {{AMC12 box|year=2019|ab=B|num-b=4|num-a=6}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 11:52, 14 February 2019
Problem
Just enough money to buy 12 red candy, 14 green candy, 15 blue candy, or n purple candy. Purple candy cost 20 cents, what is the minimum number of n?
Solution
n = 18 (SuperWill)
See Also
2019 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 4 |
Followed by Problem 6 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.