Difference between revisions of "1956 AHSME Problems/Problem 8"
(Created page with "== Solution == Simple substitution yields <cmath>8 \cdot 2^{x} = 5^{0}</cmath> Reducing the equation gives <cmath>8 \cdot 2^{x} = 1</cmath> Dividing by 8 gives <cmath>2^{x}=\...") |
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Revision as of 14:43, 31 August 2019
Solution
Simple substitution yields
![\[8 \cdot 2^{x} = 5^{0}\]](http://latex.artofproblemsolving.com/d/6/a/d6af6b14becb25e736b1d5508e3b4439c16d4091.png)
Reducing the equation gives
![\[8 \cdot 2^{x} = 1\]](http://latex.artofproblemsolving.com/0/0/2/0029b0b2a856bad4e423489d186011cd93e1c355.png)
Dividing by 8 gives
\[2^{x}=\frac{1]{8}\] (Error compiling LaTeX. Unknown error_msg)
This simply gives that 
Therefore, the answer is 
