Difference between revisions of "2002 AMC 8 Problems/Problem 15"
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+ | == Problem == | ||
+ | |||
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+ | Which of the following polygons has the largest area? | ||
+ | |||
<asy> | <asy> | ||
size(330); | size(330); | ||
Line 18: | Line 23: | ||
label("$E$", (4*6+2, 0), S);</asy> | label("$E$", (4*6+2, 0), S);</asy> | ||
− | |||
<math> \textbf{(A)}\text{A}\qquad\textbf{(B)}\ \text{B}\qquad\textbf{(C)}\ \text{C}\qquad\textbf{(D)}\ \text{D}\qquad\textbf{(E)}\ \text{E} </math> | <math> \textbf{(A)}\text{A}\qquad\textbf{(B)}\ \text{B}\qquad\textbf{(C)}\ \text{C}\qquad\textbf{(D)}\ \text{D}\qquad\textbf{(E)}\ \text{E} </math> | ||
+ | |||
+ | ==Solution== | ||
+ | Each polygon can be partitioned into unit squares and right triangles with sidelength <math>1</math>. Count the number of boxes enclosed by each polygon, with the unit square being <math>1</math>, and the triangle being being <math>.5</math>. A has 5, B has 5, C has 5, D has 4.5, and E has 5.5. Therefore, the polygon with the largest area is <math>\boxed{\textbf{(E)}\ \text{E}}</math>. | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC8 box|year=2002|num-b=14|num-a=16}} | ||
+ | {{MAA Notice}} |
Latest revision as of 04:47, 25 November 2019
Problem
Which of the following polygons has the largest area?
Solution
Each polygon can be partitioned into unit squares and right triangles with sidelength . Count the number of boxes enclosed by each polygon, with the unit square being
, and the triangle being being
. A has 5, B has 5, C has 5, D has 4.5, and E has 5.5. Therefore, the polygon with the largest area is
.
See Also
2002 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 14 |
Followed by Problem 16 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.