Difference between revisions of "1953 AHSME Problems/Problem 42"
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− | The | + | ==Problem== |
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+ | The centers of two circles are <math>41</math> inches apart. The smaller circle has a radius of <math>4</math> inches and the larger one has a radius of <math>5</math> inches. | ||
+ | The length of the common internal tangent is: | ||
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+ | <math>\textbf{(A)}\ 41\text{ inches} \qquad | ||
+ | \textbf{(B)}\ 39\text{ inches} \qquad | ||
+ | \textbf{(C)}\ 39.8\text{ inches} \qquad | ||
+ | \textbf{(D)}\ 40.1\text{ inches}\ \textbf{(E)}\ 40\text{ inches} </math> | ||
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+ | ==Solution== |
Revision as of 00:47, 4 February 2020
Problem
The centers of two circles are inches apart. The smaller circle has a radius of inches and the larger one has a radius of inches. The length of the common internal tangent is: