Difference between revisions of "1981 AHSME Problems/Problem 3"
(→Solution) |
Mathandski (talk | contribs) |
||
(5 intermediate revisions by 2 users not shown) | |||
Line 1: | Line 1: | ||
+ | ==Problem== | ||
+ | What is the least common multiple of <math>{\frac{1}{x}}</math>, <math>\frac{1}{2x}</math>, and <math>\frac{1}{3x}</math> is <math>\frac{1}{6x}</math>? | ||
+ | |||
==Solution== | ==Solution== | ||
Line 7: | Line 10: | ||
<math>\frac{6}{6x}</math> + <math>\frac{3}{6x}</math> + <math>\frac{2}{6x}</math> = <math>\frac{11}{6x}</math> | <math>\frac{6}{6x}</math> + <math>\frac{3}{6x}</math> + <math>\frac{2}{6x}</math> = <math>\frac{11}{6x}</math> | ||
− | The answer is < | + | The answer is <math>\boxed{\left(D\right) \frac{11}{6x}}</math>. |
Latest revision as of 00:16, 10 February 2020
Problem
What is the least common multiple of ,
, and
is
?
Solution
The least common multiple of ,
, and
is
.
=
,
=
,
=
.
+
+
=
The answer is .