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| − | == Problem ==
| + | #redirect [[2010 AMC 12B Problems/Problem 1]] |
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| − | Makarla attended two meetings during her <math>9</math>-hour work day. The first meeting took <math>45</math> minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?
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| − | <math>\textbf{(A)}\ 15 \qquad \textbf{(B)}\ 20 \qquad \textbf{(C)}\ 25 \qquad \textbf{(D)}\ 30 \qquad \textbf{(E)}\ 35</math>
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| − | == Solution ==
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| − | The percentage of her time spent in meetings is the total amount of time spent in meetings divided by the length of her workday.
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| − | The total time spent in meetings is <math>45 \text{ min} + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}</math>
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| − | Therefore, the percentage is <cmath>\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = \boxed{\textbf{(C)} 25}</cmath>
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| − | ==See Also==
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| − | {{AMC10 box|year=2010|ab=B|num-b=1|num-a=3}}
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