Difference between revisions of "2010 AMC 10B Problems/Problem 12"

Latest revision as of 19:40, 26 May 2020

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-The minimum possible value occurs when <math>20\%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=20</math>
+#redirect [[2010 AMC 12B Problems/Problem 6]]
-The maximum possible value occurs when <math>30\%</math> of the students who originally answered "Yes." answer "No." and the <math>50\%</math> of the students who originally answered "No." answer "Yes." In this case, <math>x=50+30=80</math>
-Subtract <math>80-20</math> to obtain an answer of <math>\boxed{\mathrm{(D)} 60}</math>