Difference between revisions of "1989 AIME Problems/Problem 9"

 
m
Line 1: Line 1:
 
== Problem ==
 
== Problem ==
 +
Let <math>a_{}^{}</math>, <math>b_{}^{}</math>, <math>c_{}^{}</math> be the three sides of a triangle, and let <math>\alpha_{}^{}</math>, <math>\beta_{}^{}</math>, <math>\gamma_{}^{}</math>, be the angles opposite them. If <math>a^2+b^2=1989^{}_{}c^2</math>, find
 +
<center><math>\frac{\cot \gamma}{\cot \alpha+\cot \beta}</math></center>
  
 
== Solution ==
 
== Solution ==
 +
{{solution}}
  
 
== See also ==
 
== See also ==
 +
* [[1989 AIME Problems/Problem 10|Next Problem]]
 +
* [[1989 AIME Problems/Problem 8|Previous Problem]]
 
* [[1989 AIME Problems]]
 
* [[1989 AIME Problems]]

Revision as of 22:09, 24 February 2007

Problem

Let $a_{}^{}$, $b_{}^{}$, $c_{}^{}$ be the three sides of a triangle, and let $\alpha_{}^{}$, $\beta_{}^{}$, $\gamma_{}^{}$, be the angles opposite them. If $a^2+b^2=1989^{}_{}c^2$, find

$\frac{\cot \gamma}{\cot \alpha+\cot \beta}$

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.

See also