Difference between revisions of "Pythagorean Theorem"

Line 6: Line 6:
  
 
<math>\frac{\sqrt{4x^2 - 1}}{3}</math>
 
<math>\frac{\sqrt{4x^2 - 1}}{3}</math>
 +
 +
<math>3-\sqrt{5}</math>

Revision as of 09:32, 26 May 2006

Right Triangles?

The formula is

$a^2 + b^2 = c^2$

$\frac{\sqrt{4x^2 - 1}}{3}$

$3-\sqrt{5}$