Difference between revisions of "1963 TMTA High School Algebra I Contest Problem 4"
Coolmath34 (talk | contribs) (Created page with "== Problem == The product of <math>3.5 \times 10^3</math> and <math>1.8 \times 10^4</math> is: <math>\text{(A)} 5.3 \times 10^7 \quad \text{(B)} \quad 6.3 \times 10^7 \quad \...") |
Coolmath34 (talk | contribs) m (→Problem) |
||
Line 2: | Line 2: | ||
The product of <math>3.5 \times 10^3</math> and <math>1.8 \times 10^4</math> is: | The product of <math>3.5 \times 10^3</math> and <math>1.8 \times 10^4</math> is: | ||
− | <math>\text{(A)} 5.3 \times 10^7 \quad \text{(B)} \quad 6.3 \times 10^7 \quad \text{(C)} \quad 6.3 \times 10^{12} \quad \text{(D)} \quad | + | <math>\text{(A)} 5.3 \times 10^7 \quad \text{(B)} \quad 6.3 \times 10^7 \quad \text{(C)} \quad 6.3 \times 10^{12} \quad \text{(D)} \quad 5.3 \times 10^1 \quad \text{(E) NOTA}</math> |
== Solution == | == Solution == |
Latest revision as of 22:25, 1 February 2021
Problem
The product of and is:
Solution
Multiply: The answer is
See Also
1963 TMTA High School Mathematics Contests (Problems) | ||
Preceded by Problem 3 |
TMTA High School Mathematics Contest Past Problems/Solutions | Followed by Problem 5 |